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frozen [14]
2 years ago
8

For which of the following reactions is ΔH∘rxn equal to ΔH∘f of the product(s)?You do not need to look up any values to answer t

his question. Check all that apply. View Available Hint(s) Check all that apply. CO(g)+12O2(g)→CO2(g) Li(s)+12F2(l)→LiF(s) C(s)+O2(g)→CO2(g) CaCO3(g)→CaO+CO2(g) 2Li(s)+F2(g)→2LiF(s) Li(s)+12F2(g)→LiF(
Chemistry
1 answer:
Nutka1998 [239]2 years ago
3 0

Answer:

Reactions 1, 3 and 5

Explanation:

First thing's first, let's ensure that all the reactions given are balanced. This is given as;

CO(g) + 1/2 O2(g )→ CO2(g)

Li(s) + 1/2 F2(l) → LiF(s)

C(s) + O2(g) → CO2(g)

CaCO3(g) → CaO + CO2(g)

2Li(s) + F2(g) → 2LiF(s)

For the condition to be valid;

- There is by convention 1 mol of product made. This means we eliminate reactions with more than one mole of compound formed. This eliminates reaction 5.

- The lements haveto be in their state at room temperature. Fluorine is a gas, not a liquid, at room temperature ans pressure, so 2 is not a correct answer.

This leaves us with reactions 1, 3 and 5 as the correct reactions that satisify the condition.

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A 0.25 m solution of the sugar sucrose (c12h22o11) in water is tested for conductivity using the type of apparatus shown. Bulb w
Anvisha [2.4K]

Sucrose is a non ionic compound. It does liberates ion when dissolved in water unlike NaCl or other salts which dissolve in water and produce respective cations and anions.

Thus if any amount of sucrose is dissolved in water, it will form non ionic aqueous solution (it will dissolve completely). Thus sucrose solution being non electrolytic will not conduct electricity in aqueous solution.

the bulb will not light up as sucrose will remain in molecular form only

6 0
2 years ago
Which statement is TRUE regarding the macroscopic and
damaskus [11]

Answer:

Chemists make observations on the macroscopic a scale that lead to conclusions about microscopic features

Explanation:

Many important chemical observations are made on the macroscopic scale. This is because, many of the scientific equipments available are not presently able to provide direct evidence about microscopic processes. Evidences obtained from macroscopic observations could serve as important insights into the nature of certain microscopic processes.

This is evident in the study of the structure of the atom. Most of the evidences that led to the deduction of the atomic structure were obtained from macroscopic evidence but ultimately provided important information about the microscopic structure of the atom.

7 0
2 years ago
According to Newton's first law of physics, what will a bowling ball do as it rolls down the bowling alley?
Nitella [24]

Answer:

Because there is no friction, Newton's first law states that the ball should continue to roll. (continue at a constant speed)

Explanation:

Unless acted upon by an unbalanced force, Newton's first law of motion states that an object at rest stays at rest and an object in motion stays in motion with the same speed and direction.

6 0
2 years ago
An unknown element, x, reacts with lithium to form the compound li2x. in other compounds this element also can accommodate up to
aliina [53]
<span>Answer Choices: 
A) Ca 
B) O 
C) Cl 
D) s</span>

<span>the formula is Li2X, so the charge on the X anion must be 2- 

the ion is X2- elements in group 6A form monatomic ions with a 2- charge. In your list that is O or Po 

If the element can accomodate 12 electrons then it can have an expanded octet. Only elements in period 3 and higher can have expanded octets. 

So you are looking for a group 6A element in period 3 or higher.
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7 0
2 years ago
Read 2 more answers
A solution is prepared by condensing 4.00 l of a gas, measured at 27°c and 748 mmhg pressure, into 58.0 g of benzene. calculate
fgiga [73]
First, we are using the ideal gas law to get n the number of moles:

PV = nRT

when P is the pressure = 748 mmHg/760 = 0.984 atm

V is the volume = 4 L

R is ideal gas constant = 0.0821

T is the temperature in Kelvin = 300 K

∴ n =  0.984atm*4L/0.0821*300

       = 0.1598 moles

when the concentration = moles * (1000g / mass)

                                         = 0.1598 * (1000g / 58 g )

                                         = 2.755 M

when the freezing point = 5.5 °C

and Kf = - 5.12 °C/m

∴ the freezing point for the solution = 5.5 °C + (Kf*m)

                                                            = 5.5 °C - (5.12°C/m * 2.755m)

                                                            = -8.6 °C

8 0
2 years ago
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