answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Helen [10]
1 year ago
8

How many moles of n2(g) would contain exactly 4.0 moles of nitrogen atoms?

Chemistry
2 answers:
VladimirAG [237]1 year ago
4 0
Each nitrogen molecule had 2 Nitrogen atoms.
So 2 moles of nitrogen gas molecules will have 4 moles of nitrogen atoms.Answer is 2moles
kaheart [24]1 year ago
4 0

Answer : The number of moles of N_2 contains are, 2 moles.

Explanation : Given,

Moles of nitrogen atoms = 4 moles

First we have to calculate the number of nitrogen atoms.

As, 1 mole of nitrogen atom contains 6.022\times 10^{23} number of nitrogen atoms

So, 4 mole of nitrogen atom contains 4\times 6.022\times 10^{23} number of nitrogen atoms

Now we have to calculate the moles of N_2 atoms.

As, 2\times 6.022\times 10^{23} number of nitrogen atoms present in 1 mole of N_2 atoms

As, 4\times 6.022\times 10^{23} number of nitrogen atoms present in \frac{4\times 6.022\times 10^{23}}{2\times 6.022\times 10^{23}}=2 mole of N_2 atoms

Therefore, the moles of N_2 atoms contains are, 2 moles

You might be interested in
Which of the following species contains manganese with the highest oxidation number?
ioda

In NaMnO₄, Mn has the highest oxidation number.

The question is incomplete, the complete question is;

Which of the following species contains manganese with the highest oxidation number?

A) Mn

B) MnF₂

C) Mn₃(PO₄)₂

D) MnCl₄

E) NaMnO₄

In order to ascertain the specie that contains manganese with the highest oxidation number, we must calculate the oxidation number of manganese in each of the species one after the other.

1) For Mn, the oxidation number of Mn is zero because the atom is uncombined.

2) For MnF₂;

Mn has an oxidation number of +2

3) For Mn₃(PO₄)₂

Mn has an oxidation number of +2

4) For MnCl₄

Mn has an oxidation number of +4

5) For NaMnO₄

Mn has an oxidation number of +7

Hence in NaMnO₄, Mn has the highest oxidation number.

Learn more: brainly.com/question/10079361

7 0
1 year ago
Justin is making a snack. He toasts a piece of bread and spreads peanut butter and jelly on it. Then he cuts an apple into sever
Leona [35]

Answer:

One chemical change- It was when he toasted the bread. The heat changed the bread so that it has the crust on the outside.

Explanation:

6 0
1 year ago
Read 2 more answers
A sample of gas occupies 10 L at STP. What
puteri [66]

Pressure is 5.7 atm

<u>Explanation:</u>

P1 = Standard pressure = 1 atm

P2 = ?  

V1 = Volume = 10L

V2= 2.4L

T1 = 0°C + 273 K = 273 K

T2 = 100°C + 273 K = 373 K

We have to find the pressure of the gas, by using the gas formula as,

$\frac{P 1 V 1}{T 1}=\frac{P 2 V 2}{T 2}

P2 can be found by rewriting the above expression as,

$P 2=\frac{P 1 \times V 1 \times T 2}{T 1 \times V 2}

Plugin the above values as,

$P 2=\frac{1 \text {atm} \times 10 L \times 373 \mathrm{K}}{273 \mathrm{K} \times 2.4 \mathrm{L}}=5.7 \text { atm }

4 0
2 years ago
Which of the following is consistent with a spontaneous process in the forward direction?
Kryger [21]

Answer:

A) ∆Suniv >0, ∆G<0, T∆Suniv >0.

Explanation:

The connection between entropy and the spontaneity of a reaction is expressed by the <u>second law of thermodynamics</u><u>: The entropy of the universe increases in a spontaneous process and remains unchanged in an equilibrium process</u>.

Mathematically, we can express the second law of thermodynamics as follows:

For a spontaneous process: ΔSuniv = ΔSsys + ΔSsurr > 0

Therefore, the second law of thermodynamics tells us that a spontaneous reaction increases the entropy of the universe; that is, ΔSuniv > 0.

If we want spontaneity expressed only in terms  of the properties of the system (ΔHsys and ΔSsys), we use the following equation:

-TΔSuniv = ΔHsys - TΔSsys < 0

That means that T∆Suniv >0.

This equation says that for a process carried out at constant pressure and temperature  T, if the changes in enthalpy and entropy of the system are such that <u>ΔHsys - TΔSsys  is less than zero, the process must be spontaneous.</u>

Finally, if the change in free energy is less than zero (ΔG<0), the reaction is spontaneous in the forward direction.

7 0
2 years ago
If 110. grams of potassium carbonate (K2CO3) is dissolved into 300. mL of solution, what is the molarity of the solution?
il63 [147K]

Answer:

2.65 M

Explanation:

Convert grams of K₂CO₃ to moles.  The molar mass is 138.205 g/mol.

(110 g)/(138.205 g/mol) = 0.796 mol

Convert milliliters of solution to liters.

300 mL = 0.300 L

Divide moles of K₂CO₃ by liters of solution.

0.796 mol/0.300 L = 2.65 mol/L = 0.265 M

6 0
1 year ago
Read 2 more answers
Other questions:
  • A 50-gram sample has a half-life of 12 days. How much material will remain after 12 days?
    6·2 answers
  • Which of the following is an example of how science can solve social problems? It can stop excessive rain from occurring. It can
    14·2 answers
  • What is the oxidation number of pt in k2ptcl6?
    8·1 answer
  • Given: CaC2 + N2 → CaCN2 + C In this chemical reaction, how many grams of N2 must be consumed to produce 265 grams of CaCN2? Exp
    10·2 answers
  • Identify the TRUE statement.
    10·1 answer
  • The percentage of silver in a solid sample is determined gravimetrically by converting the silver to Ag+ (aq) and precipitating
    5·2 answers
  • Partitioning of toxic chemicals in the environment refers to:
    11·1 answer
  • What is an azeotrope? 2. Under what conditions is it better to perform a steam distillation (instead of, say, a simple distillat
    8·1 answer
  • A bird on a long migration flies 63 kilometers per hour for 2900 kilometers. How long does he fly?
    11·1 answer
  • Suppose a metal will eject electrons from its surface when struck by yellow light. What will happen if the surface is struck wit
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!