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kompoz [17]
2 years ago
9

You have 3.50 l of solution that contains 90.0 g of sodium chloride, nacl. what is the molar mass of nacl? what is the molarity

of that solution?
Chemistry
1 answer:
nadya68 [22]2 years ago
3 0
M(NaCl) = Ar(Na) + Ar(Cl) · g/mol.
M(NaCl) = 22,99 + 35,45 · g/mol.
M(NaCl) = 58,44 g/mol.
V(NaCl) = 3,5 L.
m(NaCl) = 90 g.
n(NaCl) = m(NaCl) ÷ M(NaCl).
n(NaCl) = 90 g ÷ 58,44 g/mol.
n(NaCl) = 1,54 mol.
c(NaCl) = n(NaCl) ÷ V(NaCl).
c(NaCl) = 1,54 mol ÷ 3,5 L.
c(NaCl) = 0,44 mol/l = 0,44 M.
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Type the correct answer in the box. Express your answer to three significant figures.
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Answer:

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Explanation:

Step 1: Data given

Volume of the jar of air = 25.0 L

Number of moles argon = 0.0104 moles

Temperature = 273 K

Step 2: Calculate the pressure of argon with the ideal gas law

p*V = nRT

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⇒ with n = the number of moles of argon = 0.0104 moles

⇒ with R = the gas constant = 0.0821 L*atm/mol*K

⇒ with T = the temperature = 273 K

⇒ with V = the volume of the jar = 25.0 L

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The partial pressure of argon in the jar is 0.944 kilopascal.

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2 years ago
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0.12 mol KCl

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