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kompoz [17]
1 year ago
9

You have 3.50 l of solution that contains 90.0 g of sodium chloride, nacl. what is the molar mass of nacl? what is the molarity

of that solution?
Chemistry
1 answer:
nadya68 [22]1 year ago
3 0
M(NaCl) = Ar(Na) + Ar(Cl) · g/mol.
M(NaCl) = 22,99 + 35,45 · g/mol.
M(NaCl) = 58,44 g/mol.
V(NaCl) = 3,5 L.
m(NaCl) = 90 g.
n(NaCl) = m(NaCl) ÷ M(NaCl).
n(NaCl) = 90 g ÷ 58,44 g/mol.
n(NaCl) = 1,54 mol.
c(NaCl) = n(NaCl) ÷ V(NaCl).
c(NaCl) = 1,54 mol ÷ 3,5 L.
c(NaCl) = 0,44 mol/l = 0,44 M.
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The formula to be used for this problem is as follows:

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Solving for λ,
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Read 2 more answers
In KCI how are the valence electrons distributed
-BARSIC- [3]

Answer:

Explanation:

In KCL, the elements to combine to form KCl are K and Cl.

Potassium (K) is an element of group 1 and they're known to have 1 valence electron in its outer most orbital. This electron is donated and used for bonding. It is every element desirability to attain octet or duet electronic configuration I.e by having 2 electrons or 8 electrons in its outer orbital. Potassium has a lower electro negativity and higher ionization energy, hence it is easier to donate electron than to recieve it. Meanwhile, Chlorine (Cl) is an element of group 17 which are characterized for having 7 electrons in its outermost orbital requiring just one electron to form an octet configuration, chlorine has a higher electro negativity and lower ionization energy hence it is easier to accept electron than to donate it.

The nature of bond formed from K and Cl to give KCl is called electrovalent bonds.

Equation of reaction

K + Cl → KCl

3 0
1 year ago
A scientist performs an experiment in which they create an artificial cell with a selectively permeable membrane through which o
lozanna [386]

Answer:

Water moves into the cell

Explanation:

As shown in the question above, the cell is high in glucose and placed in a glass filled with water. This cell has a semi permeable membrane that allows only water to pass through, as the concentration of water within the cell is low, the cell will attempt to strike a balance with the medium it is inserted into. For this reason, what is likely to happen is the passage of water from the most concentrated to the least concentrated medium, that is, the water will pass from the cup to the cell.

water moves into the cell through osmosis.during osmosis water moves from a region of low concentration of solute to a region of high concentration of solute.the glucose introduced into the cell makes it more concentrated.

In this case the cell is hypertonic and water would enter into the cell through the semi permeable membrane.this membrane allows water to pass through but not glucose.this movement of water into the cell causes the cell to become turgid.

8 0
1 year ago
Given that at 25.0 ∘C Ka for HCN is 4.9×10−10 and Kb for NH3 is 1.8×10−5, calculate Kb for CN− and Ka for NH4+. Enter the Kb val
neonofarm [45]

Explanation:

Using the expression :

K_a\times K_b=K_w

Where, K_w is the dissociation constant of water.

At 25\ ^0C, K_w=10^{-14}

Thus, for HCN , K_a=4.9\times 10^{-10}

<u>K_b for CN⁻ can be calculated as:</u>

K_a\times K_b=K_w

4.9\times 10^{-10}\times K_b=10^{-14}

K_b=2.0\times 10^{-5}

Thus, for NH₃ , K_b=1.8\times 10^{-5}

<u>K_a for NH_4^+ can be calculated as:</u>

K_a\times K_b=K_w

K_a\times 1.8\times 10^{-5}=10^{-14}

K_a=5.6\times 10^{-10}

5 0
2 years ago
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