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2 years ago

On 1st January 2016 Li bought a boat for $170000

Mathematics

1 answer:

Tcecarenko [31]2 years ago

7 0

Answer: $132,376.96

Step-by-step explanation:

The cost of the boat was $170,000, but every year, the value depreciated by 8% and he bought the boat 2016.

In 2017, the boat depreciated by 8%,

8/100 * $170000 = $13,600.

$170,000 - $13600 = $156,400.

In 2018, the boat depreciated by 8%

8/100 * $156,400 = $12,512

$156,400 - $12,512 = $143,888

In 2019, the boat depreciated by 8%

8/100 * $143,888 = $11,511.04

$143,888 - $11,511.04 = $132,376.96

The current value of the boat is $132,376.96

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Answer:

The quadratic equation is f(x)=20x^{2} -400x +3000.

1. This number represents the amount of money it was sold for.

2. Vertex =(10,1000)

Step-by-step explanation:

This point represents the amount of money the computer was worth at its lowest point.

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2 years ago

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Of all the weld failures in a certain assembly, 85% of them occur in the weld metal itself, and the remaining 15% occur in the b

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Answer:

a.) 0.1028

b.) 0.6477

c.) 0.0388

d.) 3

e.) 2.55

Step-by-step explanation:

Forming a binomial Probability distribution

n = 20

Probability of success for Weld metal failure = 85%

Probability of success for base metal failure = 15%

We use the probabilit distribution formula of combination to solve the problem.

P(x=r) = nCr * p^r * q^n-r

a.) if exactly 5 are base metal failures, then p = 15 and our solution becomes:

P(x=5) = 20C5 * 0.15^5 * 0.85^15

P(x=5) = 0.1028

b.) probability that fewer than 4 are base metal failure= P(x=0) + P(x=1) + P(x=2) + P(x=3)

P(x=0) = 20C0 * 0.15^0 * 0.85^20 = 0.0388

P(x=1) = 20C1 * 0.15¹ * 0.85^19 = 0.1368

P(x=2) = 20C2 * 0.15² * 0.85^18 = 0.2293

P(x=3) = 20C3 * 0.15³ * 0.85^17 = 0.2428

Probability that fewer than 4 are base metal failures becomes: 0.038 + 0.1368 + 0.2293 + 0.2428 = 0.6477

c.) probability that none of them are results of base metal failure = P(x=0). As earlier calculated,

P(x=0) = 0.0388

d.) mean of base metal failures = np = 20*0.15 = 3

e.) standard deviation of base metal failures = √np(1-p)

=3 * (1 - 0.15) = 3 * 0.85

= 2.55

4 0

2 years ago

Last year your professor wanted to study the pattern in class grades. The following table contains a sample of grades collected

Maslowich

Answer:

mean = 78.4

median = 77.5

mode = 75

This is Right - skewed (positive skewness) distribution

Step-by-step explanation:

Mean:-

The mean (average) is found by adding all of the numbers together and dividing by the number of items and it is denoted by x⁻

mean = $\frac{64+80+75+98+75}{5}$

mean (x⁻ ) = 78.4

The mean of the given data = 78.4

Median:

The median is found by ordering the set from lowest to highest and finding the exact middle.

64 ,75, 80, 98

The middle term of the given data set = $\frac{75+80}{2} =77.5$

Mode :

The mode is the most common repeated number in a data set.

64 ,75, 75, 80, 98

in data the most common number = 75

Conclusion:-

mean = 78.4

median = 77.5

mode = 75

This is Right - skewed (positive skewness) distribution

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2 years ago

The area of the trapezoid is 24 and the bases are 3 and 5. find the height. 3 3.2 6

lorasvet [3.4K]

1. To solve this problem you must apply the formula for calcúlate the area of a trapezoid, which is shown below:

A=(B+b)h/2

A is the area of the trapezoid (A=24).
B is the larger base of the trapezoid (B=5).
b is the smaller base of the trapezoid (b=5).
h is the height of the trapezoid.

2. You must clear "h" from the formula:

A=(B+b)h/2
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3. When you susbtitute the values into h=2A/(B+b), you obtain:

h=2A/(B+b)
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2 years ago

Annie is creating a stencil for her artwork using a coordinate plane. The beginning of the left edge of the stencil falls at (2,

taurus [48]

Answer:

(A)(12, 9)

Step-by-step explanation:

Given:

The beginning of the left edge of the stencil falls at (2, −1).

A point, say Q on the stencil is at (4, 1).

Point Q divides the stencil into the ratio 1:4.

We are required to find the end of the stencil.

Mathematically, Point Q divides the stencil internally in the ratio 1:4.

For internal division of a line with beginning point $(x_1,y_1)$ and end point $(x_2,y_2)$ in the ratio m:n, we use the formula

$Q(x,y)=(\dfrac{mx_2+nx_1}{m+n} ,\dfrac{my_2+ny_1}{m+n} )$

$(x_1,y_1)=(2, -1)$ , $(x_2,y_2)=?$ , Q(x,y)=(4,1), m:n=1:4

Therefore:

$(4,1)=(\dfrac{1x_2+4*2}{1+4} ,\dfrac{1y_2+4*-1}{1+4} )\\(4,1)=(\dfrac{x_2+8}{5} ,\dfrac{y_2-4}{5} )\\$Therefore:\\\dfrac{x_2+8}{5}=4\\x_2+8=4X5\\x_2=20-8=12\\$Similarly\\\dfrac{y_2-4}{5}=1\\y_2-4=5\\y_2=4+5=9\\(x_2,y_2)=(12,9)$

The correct option is A.

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2 years ago

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