-Example of an element that has an electron distribution ending in s2p1?
1 answer:
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Answer:
a) 11.55 moles of carbon dioxide gas are formed from 3.85 mole of propane.
15.4 moles of water are formed from 3.85 mole of propane.
b)0.5176 moles of water are formed from 0.647 mole of oxygen gas.
0.1294 moles of propane are consumed.
Explanation:
a) Moles of propane = 3.85 moles
According to reaction, 1 mole of propane gives 3 moles of carbon dioxide gas.
Then 3.85 moles of propane will give:
of carbon dioxide gas.
11.55 moles of carbon dioxide gas are formed from 3.85 mole of propane.
According to reaction, 1 mole of propane gives 4 moles of water gas.
Then 3.85 moles of propane will give:
of water .
15.4 moles of water are formed from 3.85 mole of propane.
b) Moles of oxygen gas = 0.647 moles
According to reaction, 5 mole of oxygen gas gives 4 moles of water.
Then 0.647 moles of oxygen will give:
of water.
0.5176 moles of water are formed from 0.647 mole of oxygen gas.
According to reaction, 5 mole of oxygen gas reacts with 1 mole of propane.
Then 0.647 moles of oxygen will give:
of propane.
0.1294 moles of propane are consumed.
0.208 is the specific heat capacity of the metal.
Explanation:
Given:
mass (m) = 63.5 grams 0R 0.0635 kg
Heat absorbed (q) = 355 Joules
Δ T (change in temperature) = 4.56 degrees or 273.15+4.56 = 268.59 K
cp (specific heat capacity) = ?
the formula used for heat absorbed and to calculate specific heat capacity of a substance will be calculated by using the equation:
q = mc Δ T
c =
c =
= 0.208 J/gm K
specific heat capacity of 0.208 J/gm K
The specific heat capacity is defined as the heat required to raise the temperature of a substance which is 1 gram. The temperature is in Kelvin and energy required is in joules.
Answer:
The mass of the solute and the volume of the solution.
Explanation:
Hello,
In this case, given the formula of molarity:
In such a way, since the moles could not be directly measured, we must measure the mass of the solute and by using its molar mass, one could compute its moles. Moreover, since the solution is composed by the solvent (typically water) and the solute, we consequently must measure the volume of the solution needed for the preparation of such concentration-known solution. In such a way, we can actually prepare the required solution.
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