An object accelerates 3.0 m/s2 when a force of 6.0 Newton’s is applied to it. What is the mass of the object?

SnO2 is reduced by carbon according to this reaction: SnO2 + C ???? Sn + CO2. How many liters of CO2 are produced if 300.0 grams

andrew-mc [135]

Explanation:

The given reaction is as follows.

$SnO_{2} + C \rightarrow Sn + O_{2}$

a). Molar mass of $SnO_{2}$ is [(mass of Sn) + (2 × mass of O)].

Therefore, molar mass of $SnO_{2}$ = (118.7 + 2 × 16) g/mol = 150.7 g/mol

Since, it is known that number of moles equal mass divided by molar mass. So, moles of Sn will be calculated as follows.

No. of moles = $\frac{mass}{molar mass of SnO_{2}}$

= $\frac{300 g}{150.7 g/mol}$

= 2.53 mol

As it is given that 1 mole of $SnO_{2}$ produces 1 moles of Sn and 1 moles of $CO_{2}$ . Hence, 2.53 moles of $SnO_{2}$ will also produce 2.53 moles of Sn and 2.53 moles of $CO_{2}$ .

Volume of 1 mole of $CO_{2}$ at STP is 22.4 L. Therefore, volume of 2.53 moles of $CO_{2}$ will be calculated as follows.

2.53 × 22.5 L = 56.67 L

Hence, 56.67 L of $CO_{2}$ are produced if 300.0 grams of tin are produced at STP.

b). Mass of tin is given as 1800.0 g. So, number of moles will be calculated as follows.

No. of moles = $\frac{mass}{molar mass of tin}$

= $\frac{1800.0 g}{118.7 g/mol}$

= 15.2 moles

As 15.2 moles of $SnO_{2}$ produces 15.2 moles of Sn. Therefore, weight of $SnO_{2}$ will be calculated as follows.

Mass = no. of moles × molar mass of $SnO_{2}$

= 15.2 moles × 150.7 g/mol

= 2290.64 g

Hence, 2290.64 grams of $SnO_{2}$ are required to produce 1800.0 grams of tin.

c). Mass of carbon given is 100.0 grams.

No. of moles = $\frac{mass}{molar mass of carbon}$

= $\frac{100 g}{12 g/mol}$

= 8.33 moles

As, 1 mole of carbon is produced by 1 mole of tin. So, 8.33 mole of carbon will be produced by 8.33 moles of tin.

Therefore, calculate mass of tin produced as follows.

Mass = no. of moles × molar mass of Sn

= 8.33 moles × 118.7 g/mol

= 988.8 g

Hence, 988.8 grams of tin will be produced per 100 grams of carbon used.

8 0

2 years ago

The compound F2O has two lone pairs on the central oxygen atom. What's the structure of an F2O molecule? Is this compound polar

GuDViN [60]

Answer: A) Bent or angular, polar

Explanation:

The central atom oxygen has two lone pairs and two bond pairs in $OF_2$ . The number of electron pairs are 4, that means the hybridization will be $sp^3$ and the electronic geometry of the molecule will be tetrahedral. But as there are two lone pair of atoms around the central oxygen atom, repulsion between lone and bond pair of electrons is more and hence the molecular geometry will be bent shape.

The compound $OF_2$ is polar as the net dipole moment of oxygen - fluoride bonds do not cancel each other out.

3 0

1 year ago

Identify factors that account for the high phosphoryl‑transfer potential of the nucleoside triphosphates, NTPs.

lesantik [10]

Answer:

B) stabilization by hydration

C) resonance stabilization

E) increase in entropy

Explanation:

The high phosphoryl potential of ATP results from structural differences that exist between ATP and it's product of hydrolysis. There is higher phosphoryl transfer potential from ATP than glycerol 3-phosphate.

There are some factors associated to the high phosphoryl-transfer potential of ATP which are;

1.)Electrostatic repulsion

2.) Resonance stabilization

3.) Increase in entropy.

4. Stabilization by hydration.

ATP has a phosphoryl-transfer potential which lyes between high phosphoryl-potential compounds that is a derivation of fuel molecules and acceptor molecules that needs the adequate addition of a phosphoryl group for cellular needs.

8 0

2 years ago

a weather balloon is filled with 200L of helium at 27 degree Celsius and 0.950 atm. What would be the volume of the gas at -10 d

Charra [1.4K]

<u>Answer:</u> The volume when the pressure and temperature has changed is 1332.53 L

<u>Explanation:</u>

To calculate the volume when temperature and pressure has changed, we use the equation given by combined gas law. The equation follows:

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1,V_1\text{ and }T_1$ are the initial pressure, volume and temperature of the gas

$P_2,V_2\text{ and }T_2$ are the final pressure, volume and temperature of the gas

We are given:

$P_1=0.950atm\\V_1=200L\\T_1=27^oC=[273+27]K=300K\\P_2=0.125atm\\V_2=?L\\T_2=-10^oC=[273-10]K=263K$

Putting values in above equation, we get:

$\frac{0.950atm\times 200L}{300K}=\frac{0.125\times V_2}{263K}\\\\V_2=1332.53L$

Hence, the volume when the pressure and temperature has changed is 1332.53 L

5 0

2 years ago

Convert 1.21 kg to grams

MissTica

Answer:

1210 grams

Explanation:

Message me for extra info.

snap- parkguy786

7 0

2 years ago

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