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maksim [4K]
2 years ago
13

A 65-cm segment of conducting wire carries a current of 0.35 A. The wire is placed in a uniform magnetic field that has a magnit

ude of 1.24 T. What is the angle between the wire segment and the magnetic field if the force on the wire is 0.26 N

Physics
2 answers:
Artyom0805 [142]2 years ago
8 0

Answer: The angle between the wire segment and the magnetic field 66.42°

Explanation:

Please see the attachment below

Setler [38]2 years ago
8 0

Answer:

67.17°

Explanation:

From the question,

F = BILsinФ............. Equation 1

Where F = force on the wire, B = magnetic field, I = current carried by the wire, L = length of the wire, Ф = angle between the wire segment and the magnetic field.

make Ф the subject of the equation

Ф =sin⁻¹ (F/BIL)............... Equation 2

Given; F = 0.26 N, B = 1.24, I = 0.35 A, L = 65 cm = 0.65 m

Substitute into equation 2

Ф = sin⁻¹[0.26/(1.24×0.35×0.65)]

Ф = sin⁻¹(0.26/0.2821)

Ф = sin⁻¹(0.9217)

Ф = 67.17°

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Given a die, would it be more likely to get a single 6 in six rolls, at least two 6s in twelve rolls, or at least one-hundred 6s
vichka [17]

Answer:

Explanation:

In first case we are interested in one time 6 in six rolls

Thus probability = number of chances required/Total chances

= 1/6

Similarly in the second case probability = 2/12 = 1/6

In the same way in last case probability = 100/600 = 1/6

The probability is the same . Thus all the cases has equal chances  

4 0
2 years ago
A man pushes a drum of oil 10kg up an incline OA. If OA is 5m and AB is 3m, what is the potential energy of the drum at A.​
Paladinen [302]

Answer:

294 Joules

Explanation:

From the question;

  • Mass of the drum is 10 kg
  • The length of inclined surface, OA is 5 m
  • The final height of the drum on the plane AB is 3 m

We are required to determine the potential energy of the drum at A

We know that potential energy is given by the formula;

Potential energy = mgh

where m is the mass, g is the gravitational pull and h is the height

Taking g as 9.8 N/kg

Then;

Potential energy = 10 kg × 9.8 N/kg × 3 m

                            = 294 Joules

Thus, the potential energy of the drum at A is 294 Joules

6 0
2 years ago
Read 2 more answers
PLEASE ANSWER ACCURATELY DO NOT GUESS PLEASE AND THANK YOU
krek1111 [17]
Hello! I can help you with this!

1. Providence- Rhode Island
2. Philadelphia- Pennsylvania
3. St. Mary’s- Maryland
4. Plymouth and Boston- Massachusetts
5. Charleston- South Carolina
6. Savannah- Georgia
7. Hartford- Connecticut
8. New Amsterdam- New York
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4 0
2 years ago
Astronomical observatories have been available since ancient times, and many cultures set aside special sites for astronomical o
inysia [295]

Answer:

Telescope

Explanation:

Telescope is usually defined as an optical instrument that is commonly used to observe the objects in a magnified way that are located at a large distance from earth. These telescopes are comprised of lenses and curved mirrors that are needed to be arranged in a proper way in order to have a prominent look. It is commonly used by the astronomers.

This was first constructed by Hans Lippershey in the year 1608.

6 0
2 years ago
A 4.15-volt battery is connected across a parallel-plate capacitor. Illuminating the plates with ultraviolet light causes electr
FromTheMoon [43]

Answer:

a ) 2.13 X 10⁶ m/s .

b ) 1.28 X 10⁶ m/s

Explanation:

When electrons are repelled by negative plates and attracted by positive plates , it will increase their kinetic energy.

Increase in their energy = 4.15 eV

= 4.5 X 1.6 X 10⁻¹⁹ J

= 6.64 x 10⁻¹⁹ J

Initial kinetic energy

= 1/2 mv²

= 1/2 x 9.1 x 10⁻³¹ x ( 1.76 x 10⁶)²

= 14.09 X 10⁻¹⁹ J

Total energy

= 6.64 x 10⁻¹⁹+14.09 X 10⁻¹⁹

= 20.73 x 10⁻¹⁹

If V be the increased velocity

1/2 m V² = 20.73 X 10⁻¹⁹

.5 X 9.1 X 10⁻³¹ V² = 20.73 X 10⁻¹⁹

V = 2.13 X 10⁶ m/s .

b ) When electrons are released from positive plate , their speed are reduced because of attraction between electrons and positively charge plates.

Initial kinetic energy

= 14.09 x 10⁻¹⁹ J (see above )

reduction in kinetic energy  

= 6.64 x 10⁻¹⁹ J ( See above )

Total energy with electron -

= 14.09 x 10⁻¹⁹  - 6.64 x 10⁻¹⁹

= 7. 45 x 10⁻¹⁹ J .

If V be the energy of electrons reaching the negative plate,

1/2 m V² =7. 45 x 10⁻¹⁹

V = 1.28 X 10⁶ ms⁻¹

6 0
2 years ago
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