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2 years ago

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What net force is required to push a sofa with a mass of 59 kilograms so that it accelerates at 9.75 meters/secondÆ? (Assume a f

lat, frictionless surface.)
A. 6.1 Newtons
B. 59 Newtons
C. 5.8 x 10^2 newtons
D. 6.0 x 10^2 newtons

2 answers:

Ilia_Sergeevich [38]2 years ago

7 0

We Know, F = m*a
Here, m = 59 Kg
a = 9.75 m/s²

Substitute their values in the expression,
F = 59*9.75
F = 575.25 Kg.m/s²

So, your final answer is 575.25 N

Hope this helps!

Marizza181 [45]2 years ago

7 0

Answer : $F=5.8\times 10^2\ Newtons$ amount of force is required to push a sofa.

Explanation :

It is given that,

The mass of sofa, m = 59 kg

Acceleration, $a=9.75\ m/s^2$

According to Newton's second law of motion :

F = ma

m is the mass and a is the acceleration produced.

$F=59\ kg\times 9.75\ m/s^2$

F = 575.25 Newtons

$F=5.75\times 10^2\ Newtons$

or

$F=5.8\times 10^2\ Newtons$

Hence, this is the required solution.

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