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Maru [420]
2 years ago
11

What net force is required to push a sofa with a mass of 59 kilograms so that it accelerates at 9.75 meters/secondÆ? (Assume a f

lat, frictionless surface.)
A. 6.1 Newtons
B. 59 Newtons
C. 5.8 x 10^2 newtons
D. 6.0 x 10^2 newtons
Physics
2 answers:
Ilia_Sergeevich [38]2 years ago
7 0
We Know, F = m*a
Here, m = 59 Kg
a = 9.75 m/s²

Substitute their values in the expression, 
F = 59*9.75
F = 575.25 Kg.m/s²

So, your final answer is 575.25 N

Hope this helps!
Marizza181 [45]2 years ago
7 0

Answer : F=5.8\times 10^2\ Newtons amount of force is required to push a sofa.

Explanation :

It is given that,

The mass of sofa, m = 59 kg

Acceleration, a=9.75\ m/s^2

According to Newton's second law of motion :

F = ma

m is the mass and a is the acceleration produced.

F=59\ kg\times 9.75\ m/s^2

F = 575.25 Newtons

F=5.75\times 10^2\ Newtons

or

F=5.8\times 10^2\ Newtons

Hence, this is the required solution.

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E. downward and constant

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Answer:

Option b

Explanation:

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7 0
2 years ago
Two small aluminum spheres, each of mass 0.0250 kilograms, areseparated by 80.0 centimeters.
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Answer:

Total number of electrons

N = 7.25 \times 10^{24}

electrons removed from each sphere

N = 5.27 \times 10^{15}

Fraction of electrons transferred is given as

f = 7.27 \times 10^{-10}

Explanation:

As we know that moles is defined as

n =\frac{mass}{molar mass}

n = \frac{0.0250}{0.026982}

n = 0.93

so number of atoms of Al in each sphere is given as

N = 0.93(6.02 \times 10^{23})

N = 5.58 \times 10^{23}

Now number of electrons in each atom is given as

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total number of electrons in each sphere is

N = 13 \times (5.58 \times 10^{23})

N = 7.25 \times 10^{24}

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F= \frac{kq_1q_2}{r^2}

1.00 \times 10^4 = \frac{(9\times 10^9)q^2}{0.80^2}

q = 8.4 \times 10^{-4} C

now we have

q = Ne

8.4 \times 10^{-4} = N(1.6 \times 10^{-19}

N = \frac{(8.4 \times 10^{-4})}{1.6 \times 10^{-19}}

N = 5.27 \times 10^{15}

Fraction of electrons transferred is given as

f = \frac{5.27 \times 10^{15}}{7.25 \times 10^{24}}

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The distance they have traveled is the same, so the displacement is the same, but the velocity is not, so this is false.

e. it has the same position, displacement and velocity as A

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