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Svetradugi [14.3K]
2 years ago
13

Mr. And Mrs. Harper are planning to install a deck and a garden. Help them determine which of the two choices below is most effi

cient. Plan A: Deck measures 18 feet by 25 feet Garden measures 9 feet by 12 feet. Plan B: Deck Measures 16 feet by 20 feet. Garden measures a radius of 5 feet
Mathematics
1 answer:
Iteru [2.4K]2 years ago
4 0

Answer:

Plan A

Step-by-step explanation:

To find the better plan, you must find which plan has a bigger area.

First, we're going to find Plan A using the area formula (A = L * W)

A = L * W

A = 18 * 25

A = 450

Now we must find the area of the garden.

A = 9 * 12

A = 108

Add both areas together to get the area of Plan A.

450 + 108 = 558. Plan A has an area of 558 feet.

Second, Now we're going to find Plan B's area using the circle formula and area formula.

To find the area of the deck, use the formula.

A = L * W

A = 16 * 20

A = 320  

Now we will find the area of the garden.

Since the garden is a circle and we are given the radius, we will use the formula A = πr²

A = 3.14 * 5²

A = 3.14 * 25

A = 78.5

Now add both areas together.

78.5 + 320 = 398.5. Plan B has an area of 398.5 feet.

558 > 398.5, so <u>Plan A is more efficient, judging solely on size.</u>

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Answer:

10:9

Step-by-step explanation:

First ratio is 5:4. 4 is equal to Henry class

If you múltiply the ratio by 2 you get

10:8, This ratio can be compared because now Henry class has 8

2(5:4)

10:8

8:9

Meaning that the answer is 10:9

7 0
2 years ago
Anna set up a lemonade stand on her block over the summer. She recorded each day’s high temperature and the number of cups of le
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Answer:

Residual = -2

The negative residual value indicates that the data point lies below the regression line.

Step-by-step explanation:

We are given a linear regression model that relates daily high temperature, in degrees Fahrenheit and number of lemonade cups sold.

y = -34+ \frac{3}{5}  x

Where y is the number of cups sold and x is the daily temperature in Fahrenheit.

Residual value:

A residual value basically shows the position of a data point with respect to the regression line.

A residual value of 0 is desired which means that the regression line best fits the data.

The Residual value is calculated by

Residual = Observed value - Predicted value

The predicted value of number of lemonade cups is obtained as

y = -34+ \frac{3}{5} (95)\\\\y = -34+ 3 (19)\\\\y = -34+ 57\\\\y = 23

So the predicted value of number of lemonade cups is 23 and the observed value is 21 so the residual value is

Residual = Observed value - Predicted value

Residual = 21 - 23

Residual = -2

The negative residual value indicates that the data point lies below the regression line.

7 0
2 years ago
While driving home for the holidays, you can’t seem to get Little’s Law out of your mind. You note that your average speed of tr
suter [353]

Answer:

1,200 cars per hour

Step-by-step explanation:

Let's suppose the car flow is constant and based on the observations stated in the problem.

If we set and imaginary car counter where your car is, then there are 25 cars in ¼ of a mile (including yours) going at your same speed.

Now compute how long it will take to travel ¼ mile. As your speed is constant 60 mph, we can cross multiply  

60 miles -----------> 1 hour

¼ of a mile --------> x hours

and

60/ (¼) = 1/x ---------> x = 1/240 hours.

This means that in 1/240 hours the 25 cars will be passing the counter.

Now compute how many cars will pass through our counter in 1 hour. Again, cross multiplying

1/240 hours -------> 25 cars

1 hour --------------> x cars

and

1/240 = 25/x -------> x = 25*240 = 1,200 cars.

So, the flow rate of the highway (going in your direction) in cars per hour is 1,200 cars per hour.

7 0
2 years ago
An exponential function and a quadratic function are graphed below. Which of the following is true of the growth rate of the fun
aleksley [76]
Given an exponential function, say f(x), such that f(0) = 1 and f(1) = 2 and a quadratic finction, say g(x), such that g(0) = 0 and g(1) = 1.

The rate of change of a function f(x) over an interval
a \leq x \leq b
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\frac{f(b)-f(a)}{b-a}

Thus, the rate of change (growth rate) of the exponential function, f(x) over the interval
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\frac{f(1)-f(0)}{1-0} = \frac{2-1}{1} =1

Similarly, the rate of change (growth rate) of the quadratic function, g(x) over the interval
0 \leq x \leq 1
is given by
\frac{g(1)-g(0)}{1-0} = \frac{1-0}{1} =1

Therefore, the exponential grows at the same rate as the quadratic in the interval <span>0 \leq x \leq 1.</span>
3 0
2 years ago
Read 2 more answers
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navik [9.2K]

Answer:

Martin drove 53,558 miles.

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If you add up the amount of miles his son and wife drove, you get 32,898. To get the answer, you would subtract that from the total number of miles to get 53,558.

3 0
2 years ago
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