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I am Lyosha [343]
2 years ago
12

The top of the rectangular box is 15 cm by 20 cm and its hight is 4 cm. And ant begins at one corner of the box and walks along

the edges. It touches all 8 corners what is the shortest distance in cm that the ant may travel

Mathematics
1 answer:
Nimfa-mama [501]2 years ago
8 0

Answer:

92 cm

Step-by-step explanation:

Look at the attached photo, it may give you a better understanding

As we know it touches all 8 corners so the shortest distance in cm that the ant may travel is:

15+ 4+15+4 +20 + 15 +15 + 4 = 92 cm

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After placing an equation into his calculator Rob got the following table. He then determine that X=6 when f (x) = -4 is he corr
icang [17]

Answer:

No, unless the function decides to follow a different pattern. See more explanation below.

Step-by-step explanation:

He is wrong, the table doesn't tell us what happens at x=6.

It does tell us the following:

1) When x=-4, f(x)=6.

2) When x=-2, f(x)=3.

3) When x=0, f(x)=-1.

4) When x=2, f(x)=-4.

So maybe he got it the x and f(x) value switched in his brain.

Because according to 1) x=-4 when f(x)=6.

If the points keep having x increase while y decreases, then every x>2 will have a y less than -4 correspond to it.

4 0
2 years ago
two taps drip together at exactly 1:00pm. one tap then drips again every 68 sec while the other tap continues to drip every 72 s
N76 [4]
The least common multiple of 68 and 72 is 1224 so that means we have to add 1224 minutes to 1:00 pm. Convert that to 24 hour time: 1300. 1224 ÷ 60 is 20.4. so the answer will be 1:20 pm.
P.S. delete this answer if it is wrong and tell me the right answer

5 0
2 years ago
The number of home runs scored by a certain team in one baseball game is a random variable with the distribution x 0 1 2 P(x) 0.
DanielleElmas [232]

Answer: E(Y) = 1.6 and Var(Y)=1.12

Step-by-step explanation:

Since we have given that

X       0        1       2

P(X)   0.4   0.4    0.2

Here, number of games = 2

So, Y=X_1+X_2

Since X_1\ and\ X_2 are independent variables.

so, E[Y]=2E[X]\\\\Var[Y]=2Var[X]

So, we get that

E(X)=0.4\times 0+0.4\times 1+0.2\times 2=0.8\\\\and Var[x]=E[x^2]-(E[x])^2\\\\E[x^2]=0\times 0.4+1\times 0.4+4\times 0.2=1.2\\\\So, Var[x]=1.2-(0.8)^2\\\\Var[x]=1.2-0.64=0.56

So, E[y]=2×0.8=1.6

and Var[y]=2×0.56=1.12

Hence, E(Y) = 1.6 and Var(Y)=1.12

5 0
2 years ago
A shipment of 7 television sets contains 2 defective sets. A hotel makes a random purchase of 3 of the sets. If x is the number
serg [7]

Answer:

The probability distribution is

X    :        0              1                 2

f(X) :       2/7          4/7               1/7

Step-by-step explanation:

Let x is the number of defective sets purchased by the hotel.

Total number of television sets = 7

Total number of defective television sets = 2

Since there are 2 defective television sets and hotel purchase 3 sets, So, X=0,1,2.

If X=0,

P(X=0)=\frac{^5C_3}{^7C_3}=\frac{10}{35}=\frac{2}{7}

If X=1,

P(X=1)=\frac{^5C_2\cdot ^2C_1}{^7C_3}=\frac{10\cdot 2}{35}=\frac{4}{7}

If X=2,

P(X=2)=\frac{^5C_1\cdot ^2C_2}{^7C_3}=\frac{5\cdot 1}{35}=\frac{1}{7}

The probability distribution is

X    :        0              1                 2

f(X) :       2/7          4/7               1/7

The probability histogram is shown below.

3 0
2 years ago
Jordan used the distributive property to write an expression that is equivalent to 6c – 48. 6c - 48 is equivalent to 6(c - 48) I
Katyanochek1 [597]
It’s incorrect.

The correct answer is 6(c - 8)
8 0
2 years ago
Read 2 more answers
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