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Rudiy27
2 years ago
14

A fish is removed from a contaminated lake. You determine that a particular toxin (X) is present in its cells at concentration X

= 1,500 μg/L. You place the fish in a tank full of clean water (X = 0 μg/L), and measure the toxin concentration in the fish cells each day for the next 10 days.
After making your hypothesis, you test it by measuring the toxin levels in the fish at various times during its 10 days in the tank. You observe that the level of toxin in the fish drops from 1,500 μg/L to 750 μg/L and then stabilizes at 750 μg/L. You test the water in the tank and find that after it stabilizes, toxin is present in the water at concentration 750 μg/L also. What can you do to continue to reduce the toxin level in the fish below 750 μg/L?
Chemistry
1 answer:
netineya [11]2 years ago
3 0
The level of toxins in the fish's cell is equivalent to the level of toxins in the water. Therefore, in order to reduce the toxins further, we should replace the now contaminated water with clean water. After the level of toxins in the fish's cell stops reducing, we replace the water with clean water once again.
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A gas has a mass of 3.82 g and occupies a volume of 0.854 L. The temperature in the laboratory is 302 K, and the air pressure is
4vir4ik [10]

m = given mass of gas = 3.82 g

M = molar mass of gas = ?

T = temperature of laboratory = 302 K

P = air pressure = 1.04 atm = 1.04 x 101325 pa

V = volume of gas = 0.854 L = 0.854 x 10⁻³ m³

using the ideal gas equation

PV = (m/M) RT

inserting the above values

(1.04 x 101325) (0.854 x 10⁻³) = (3.82/M) (8.314) (302)

M = 106.6 g

hence the molar mass of the gas comes out to be 106.6 g

3 0
2 years ago
Identify the nuclide produced when plutonium-239 decays by alpha emission: 239 94pu→42he + ? express your answer as an isotope u
Galina-37 [17]

1. Answer is ₉₂²³⁵U<span>

<span>Since this is an alpha emission the atomic number of the daughter nucleus decreases by 2 while mass number decreases by 4 compared to parent atom. Since parent atom has 94 as atomic number the daughter atom should have </span>94 - 2 = 92 as atomic number<span> <span>and </span></span>239 - 4 = 235 as mass number. <span>

</span></span>₉₄²³⁹Pu → ₂⁴He + ₉₂²³⁵U<span>

2. </span><span>Answer is </span>₉₁²³⁴Pa<span>

</span><span>Since this is a beta emission, a neutron is converted into a proton while emitting an electron. Hence atomic number increases by 1 compared to mass number but mass number remains as same. Hence, the </span>atomic number of the daughter atom<span> <span>should be </span></span>90 + 1 = 91<span> <span>which belongs to </span></span>Pa<span>. But the </span>mass number is same as 234.<span>

</span>₉₀²³⁴Th → ₋₁⁰e + ₉₁²³⁴Pa<span>
</span><span>
3.<span> <span>Answer is </span></span></span>₈¹⁸O<span>

</span><span>Since this is a positron emission, a proton is converted into a neutron while emitting an positron. Hence atomic number decreases by 1 compared to mass number but mass number remains as same. Hence, the </span>atomic number of the daughter atom<span> should be </span>9- 1 = 8 <span>which belong to </span>O<span>. But the </span>mass number is same as 18.<span>

</span>₉¹⁸F → ₊₁⁰e + ₈¹⁸O<span>

4. </span>Answer is ₈₀²⁰¹Hg<span>

</span><span>This is an </span><span>electron capture decay. </span>A<span> proton is converted into a neutron by emitting a gamma ray. In this process </span>mass number remains as same<span> <span>as parent atom which is </span></span>201<span>, but the </span>atomic number is decreased by 1<span> <span>than parent atom. Hence atomic number of daughter nucleus is 81 -1 = </span></span>80 <span>which belongs to </span>Hg.<span>
</span><span>
</span>₈₁²⁰¹Tl +  ₋₁⁰e →  ₀⁰γ + ₈₀<span>²⁰¹Hg</span>

6 0
2 years ago
Based on the values you obtained for δh∘rxn, which of the reactions would you expect to be thermodynamically favorable and which
QveST [7]
Following reactions are involved in present reaction
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2) </span><span>2Fe(s)     +     2Na+(aq)      →        Fe2+(aq)      +       2Na(s)     +   392.3kJ
</span>3)  <span>2K(s)     +      2H2O(l)      →      2KOH(aq)       +H2(g)       −393.1kJ

In above reaction, reaction 1 and 3 has negative value of </span>δh∘f, while reaction 2 has posiyive value of <span>δh∘f. As per the sign convention positive sign indicates that heat is given out during the reaction, while negative sign indicates heat is to be supplied for reaction to occur. In alternative words, product formed in reaction 2 is stable as compared to reactant. Hence, it is thermodynamically favorable. </span>
7 0
2 years ago
Click the "draw structure" button to launch the drawing utility. Propane (CH3CH2CH3) has both 1° and 2° hydrogens. Draw the carb
OlgaM077 [116]

Answer:

a) find attached image 1

b) find attached image 2

Explanation :

The more stable radical is formed by a reaction with smaller bond dissociation energy.

since the bond dissociation for cleavage of the bond to form primary free radical is higher, more energy must be added to form it. This makes primary free radical higher in energy and therefore less stable than secondary free radical.

6 0
2 years ago
Methanol (ch3oh) can react with oxygen gas to produce formaldehyde (h2co) and water. How many mole of formaldehyde can be produc
Umnica [9.8K]
<h2>The number of moles of formaldehyde can be produced by reacting 4.0 moles of methanol with 4.0 moles of oxygen gas is <u>8 moles</u></h2>

<u> explanation</u>

write   a balanced chemical reaction

that is 2 CH3OH (l) +  O2 (g) →  2HCOH (l)+ 2H2O (l)

from the reaction above  2 moles of CH3OH reacted with 1 moles of O2 to form 2 moles of HCOH and two moles of H2O

This imply that O2 is the limiting reagent ,therefore by use of mole ratio between  O2 : HCOH which is 1 :2 the moles of HCOH= 2 x4 =  8 moles

5 0
2 years ago
Read 2 more answers
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