An outstretched arm of a person is held at an angle θ= 16.0° below the horizon and a 16.0 N weight is placed in the hand. The sh
1 answer:
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Ans: Beat Frequency = 1.97Hz
Explanation:
The fundamental frequency on a vibrating string is
<span> -- (A)</span>
<span>here, T=Tension in the string=56.7N,
L=Length of the string=0.66m,
m= mass = 8.3x10^-4kg/m * 0.66m = 5.48x10^-4kg </span>
Plug in the values in Equation (A)
<span>so </span>
<span> = 197.97Hz </span>
<span>the beat frequency is the difference between these two frequencies, therefore:
Beat frequency = 197.97 - 196.0 = 1.97Hz
-i</span>
Explanation:
The fundamental frequency on a vibrating string is
<span>here, T=Tension in the string=56.7N,
L=Length of the string=0.66m,
m= mass = 8.3x10^-4kg/m * 0.66m = 5.48x10^-4kg </span>
Plug in the values in Equation (A)
<span>so </span>
<span>the beat frequency is the difference between these two frequencies, therefore:
Beat frequency = 197.97 - 196.0 = 1.97Hz
-i</span>
Answer:
The acceleration is found as:
a = 1000 km/h²
Explanation:
Initial speed of the plane = 450 km/h
Final speed of the plane = 750 km/h
Time taken = 0.3 h
Acceleration can be defined as the change of speed of the object divided by the time taken to bring that change
Acceleration is given as:
where v(f) = 750 km/h , v(i) = 450 km/h , t = 0.3 h
Substitute the values in the equation of acceleration
This is the found result