I attached the missing picture.
We can figure this one out using the law of conservation of energy.
At point A the car would have potential energy and kinetic energy.

Then, while the car is traveling down the track it loses some of its initial energy due to friction:

So, we know that the car is approaching the point B with the following amount of energy:

The law of conservation of energy tells us that this energy must the same as the energy at point B.
The energy at point B is the sum of car's kinetic and potential energy:

As said before this energy must be the same as the energy of a car approaching the loop:

Now we solve the equation for

:
Answer:
In hot gases , the atoms keeps colliding with each other and sometimes the energy liberated during collision takes the electron to a higher level,thus, .The object is a cloud of hot gas and finally the electron returns back emitting photon
Would presume you are asked to find the volume, since there is no second volume.
By General Gas Law:
P₁V₁/T₁ = P₂V₂/T₂
1.6 * 168 /255 = 1.3*V₂/285
V₂ = 1.6 * 168 * 285 / (1.3*255)
V₂ = 231.095
Final volume ≈ 231 cm³
The angular velocity of the orbit about the sun is:
w = 1 rev / year = 1 rev / 3.15 × 10^7 s
Now in 1 rev there is 360° or 2π rad, therefore:
w = 2π rad / 3.15 × 10^7 s
To convert in linear velocity, multiply the rad /s by the
radius:
v = (2π rad / 3.15 × 10^7 s) * 93,000,000 miles
<span>v = 18.55 miles / s = 29.85 km / s</span>