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Leto [7]
2 years ago
6

a shopper pushes a cart 40.0m south down one aisle and then turns 90.0 degrees and moves 15.0m. He then makes another 90.0 degre

e turn and moves 20.0m. Find the shoppers total displacement. (there could be more than one correct answer)
Physics
1 answer:
valentinak56 [21]2 years ago
8 0

Answer:

Explanation:

The displacement is the distnce of the shopper from the starting point.

Sum of movement along the vertical = 40-20 = 20m

Movement along the horizontal (x direction) = 15.0m

Displacement will be gotten using the pythagoras theorem.

d = √20²+ 15²

d = √400+225

d = √625

d = 25.0m

Hence the shoppers total displacement is 25.0m

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. A girl runs and jumps horizontally off a platform 10m above a pool with a speed of 4.0m/s. As soon as she leaves the platform,
faust18 [17]

Answer:

2.39 revolutions

Explanation:

As she jumps off the platform horizontally at a speed of 10m/s, the gravity is the only thing that affects her motion vertically. Let g = 10m/s2, the time it takes for her to fall 10m to water is

h = gt^2/2

10 = 10t^2/2

t^2 = 2

t = \sqrt{2} = 1.414 s

Knowing the time it takes to fall to the pool, we calculate the angular distance that she would make at a constant acceleration of 15 rad/s2:

\theta = \alpha t^2/2

\theta = 15 * 2/2 = 15 rad

As each revolution is 2π, the total number of revolution that she could make is: 15 / 2π = 2.39 rev

3 0
2 years ago
evaluate the numerical value of the vertical velocity of the car at time t=0.25 s using the expression from part d, where y0=0.7
likoan [24]

Given :

Displacement , y = 0.75 m .

Angular acceleration , \alpha=0.95\ s^{-2} .

Initial angular velocity , \omega_o=6.3\ s^{-1} .

To Find :

The value of vertical velocity after time t = 0.25 s .

Solution :

By equation of circular motion is given by :

\omega=\omega_o+\alpha t

Putting all given values we get :

\omega=6.3+0.95\times 0.25\\\\\omega= $$6.5375\ s^{-1}

Now , vertical velocity is given by :

v=y\omega\\\\v=0.75\times 6.5375\ m/s\\\\v=4.90\ m/s

Therefore , the numerical value of the vertical velocity of the car at time t=0.25 s is 4.90 m/s .

Hence , this is the required solution .

8 0
2 years ago
A car is traveling at 20 meters/second and is brought to rest by applying brakes over a period of 4 seconds. What is its average
frez [133]
 (u) = 20 m/s 
(v) = 0 m/s 
<span> (t) = 4 s 
</span>
<span>0 = 20 + a(4) 

</span><span>4 x a = -20 
</span>
so, the answer is <span>-5 m/s^2. or -5 meter per second</span>
8 0
2 years ago
Read 2 more answers
An airplane is delivering food to a small island. It flies 100 m above the ground at a speed of 150 m/s .
miss Akunina [59]

Answer:

The airplane should release the parcel 6.7*10^2 m before reaching the island

Explanation:

The height of the plane is y_0=100m, and its speed is v=150 m/s

When an object moves horizontally in free air (no friction), the equation for the y measured with respect to ground is

y=y_0 - \frac{gt^2}{2}    [1]

And the distance X is

x = V.t     [2]

Being t the time elapsed since the release of the parcel

If we isolate t from the equation [1] and replace it in equation [2] we get

X = V . \sqrt{\frac{2y_0}{g}}

Using the given values:

x = 150 m/s  \sqrt{\frac{2\times 100m}{9.8 m/sec^2}}

x = 6.7*10^2 m

4 0
2 years ago
Suppose that the current in the solenoid is i(t. within the solenoid, but far from its ends, what is the magnetic field b(t due
Mkey [24]
The answer is B(t) = constants x I(t)

Please take precaution on the point that it is an independent field of its radial position, if the point is measured well in the solenoid. (also the radial position is the axis of its symmetry)
7 0
2 years ago
Read 2 more answers
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