A small cylinder rests on a circular turntable that is rotating clockwise at a constant speed. Which set of vectors gives the di
rection of the velocity v with arrow, acceleration a with arrow of the cylinder, and the net force ΣF with arrow that acts on it?
(A) 3
(B) 4
(C) 1
(D) 2
(A) 3
(B) 4
(C) 1
(D) 2
1 answer:
The question is missing the diagram. Also, the choices must have pictorial representation. So, I have attached the missing diagram and the pictorial representation of the vectors.
Answer:
The correct representation is attached below. Force and acceleration will be towards the center of rotation while the velocity will be along the tangent to the circular motion. <u>Option (D).</u>
Explanation:
From the figure, we can conclude the following points:
1. The cylinder is under a uniform circular motion as the circular table is moving at constant speed.
2. For a circular motion, velocity acts along the tangent to the circular path.
3. For a circular motion, centripetal force acts on the body that causes it move around a circular path.
4 The direction of the centripetal force is radially inward towards the center of rotation.
5. The centripetal force causes a centripetal acceleration acting on the body.
6. From Newton's second law, the net acceleration of a body is in the same direction as that of the net force acting on it. So, centripetal acceleration also acts in the radially inward direction.
Therefore, from the above conclusions, it is clear that velocity will act in the horizontal direction at the given instance of time and force and acceleration will act vertically down for the given instance.
This is shown in the picture below. The option (D).
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Solution :
Mass of the particle = M
Speed of travel = v
Energy of one photon after the decay which moves in the positive x direction = 233 MeV
Energy of second photon after the decay which moves in the negative x direction = 21 MeV
Therefore, the total energy after the decay is = 233 + 21
= 254 MeV
So by the law of conservation of energy, we have :
Total energy before the decay = total energy after decay
So, the total relativistic energy of the particle before its decay = 254 MeV
A. The difference in the two ball's time in the air is 3 seconds
B. The velocity of each ball as it strikes the ground is 24.5 m/s
C. The balls 0.500 s after they are thrown are 14.7 m apart
<h3>Further explanation</h3>Acceleration is rate of change of velocity.
<em>a = acceleration ( m/s² )</em>
<em>v = final velocity ( m/s )</em>
<em>u = initial velocity ( m/s )</em>
<em>t = time taken ( s )</em>
<em>d = distance ( m )</em>
Let us now tackle the problem!
<u>Given:</u>
Initial Height = H = 19.6 m
Initial Velocity = u = 14.7 m/s
<u>Unknown:</u>
A. Δt = ?
B. v = ?
C. Δh = ?
<u>Solution:</u>
<h2>Question A:</h2><h3>First Ball</h3>The difference in the two ball's time in the air is:
The velocity of each ball as it strikes the ground is 24.5 m/s
<h2>Question C:</h2><h3>First Ball</h3>The difference in the two ball's height after 0.500 s is:
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Grade: High School
Subject: Physics
Chapter: Kinematics
Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle
Answer:
B.
Explanation:
One of the ways to address this issue is through the options given by the statement. The concepts related to the continuity equation and the Bernoulli equation.
Through these two equations it is possible to observe the behavior of the fluid, specifically the velocity at a constant height.
By definition the equation of continuity is,
In the problem is
, then
<em>Here we can conclude that by means of the continuity when increasing the Area, a decrease will be obtained - in the diminished times in the area - in the speed.</em>
For the particular case of Bernoulli we have to
For the previous definition we can now replace,
<em>Expressed from Bernoulli's equation we can identify that the greater the change that exists in pressure, fluid velocity will tend to decrease</em>
The correct answer is B: "If we increase A2 then by the continuity equation the speed of the fluid should decrease. Bernoulli's equation then shows that if the velocity of the fluid decreases (at constant height conditions) then the pressure of the fluid should increase"