Question

City A and City B had two different temperatures on a particular day. On that day, four times the temperature of City A was 8° C more than 3 times the temperature of City
b. The temperature of City A minus twice the temperature of City B was −3°
c. What was the temperature of City A and City B on that day?

Answer 1

Answer: option A

Step-by-step explanation:

The temperature of city A was 5°C, and the temperature of city B was 4°.

Answer 2

A - the temperature of city A
b - the temperature of city B

Four times the temperature of city A was 8°C more than 3 times the temperature of city B.
$4a=3b+8$

The temperature of city A minus twice the temperature of city B was −3°C.
$a-2b=-3$

Set up a system of equations:
$4a=3b+8 \\ a-2b=-3 \ \ \ \ \ \ \ |\times (-4) \\ \\ 4a=3b+8 \\ \underline{-4a+8b=12} \\ 8b=3b+8+12 \\ 8b-3b=8+12 \\ 5b=20 \ \ \ \ \ \ \ \ \ \ \ \ \ |\div 5 \\ b=4 \\ \\ a-2b=-3 \\ a-2 \times 4=-3 \\ a-8=-3 \ \ \ \ \ \ \ \ \ |+8 \\ a=5$

The temperature of city A was 5°C, and the temperature of city B was 4°.