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rodikova [14]
2 years ago
13

At a grocery store, blueberries come packaged in 8-ounce containers for $2.80. At a farmer's market, blueberries cost $4.20 for

14 ounces. There are 16 ounces in one pound. Which statement accurately compares the cost of blueberries?
Mathematics
2 answers:
saveliy_v [14]2 years ago
7 0
                            Grocery Store:                    Farmer's Market
Cost                        $2.80                                     $4.20
Weight                       8 oz                                       14 oz
Unit Cost
Cost ÷ Weight         $0.35 per oz                         $0.30 per oz
1 lb = 16 oz               16 oz                                      16 oz
Cost per pound       
Unit Cost * 16oz     $5.60 per lb                          $4.80 per lb

The blueberries in the farmer's market costs less than the blueberries from the grocery store. 

One pound of blueberries from the farmer's market is cheaper by $0.80 than the blueberries from the grocery store. ($5.60 - $4.80 = $0.80)
Leni [432]2 years ago
4 0

Answer:

Step-by-step explanation: C) blueberries are 0.80 per pounds expensive at the farmers market

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If the ratio of the sides of two squares is 3:1, what is the ratio of their perimeters?
Anvisha [2.4K]

Answer:

Ratio of the perimeters =3:1

Step-by-step explanation:

We have given that : Ratio of the sides of two squares is 3:1

To find : Ratio of their perimeters

Solution : Let the length of the sides are 3:1 = 3x : x

                  Formula of perimeter of square = 4(side)

Using the formula ,

Perimeter of 1 square = 4×3x= 12x

Perimeter of 2 square = 4×x= 4x

Ratio of the perimeter of 1 square and 2 square = 12x : 4x

                                                                                 = 3 : 1


8 0
2 years ago
The equation 9+12m=6+15(m-1) models the following situation: Movie-rental company A charges a sign-up fee of $9 plus $12 per mon
Ganezh [65]

Answer:

3m = 18

Step-by-step explanation:

9 + 12m = 6 + 15(m - 1)

9 + 12m = 6 + 15m - 15

3m = 18

6 0
2 years ago
Read 2 more answers
All of the following expressions are equal to N except _____. |−N| −(−N) |N| −N
Maksim231197 [3]

Answer:

D. -N

Step-by-step explanation:

Our four given expressions are:

A. |-N|

B. -(-N)

C. |N|

D. -N

The | | symbols represent absolute value, which is the distance from the value within the two lines and 0; essentially since it measures distance, absolute value always outputs a positive value.

In choice A, we have |-N|, which means the distance between -N and 0. Well, the distance will simply be N, which is equal to N. Eliminate A.

In choice B, we have -(-N). Double negatives signal that they will cancel out to become positive, so -(-N) = N. Eliminate B.

In choice C, we have |N|, which means the distance between N and 0. This is clearly just N, so eliminate C.

In choice D, we have -N, which denotes "negative N". Clearly, "negative N" (-N) is not the same as "positive N" (N), so D is the answer.

<em>~ an aesthetics lover</em>

3 0
2 years ago
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Verify the given linear approximation at a = 0. Then determine the values of x for which the linear approximation is accurate to
nikklg [1K]

Answer:

Part 1)

See Below.

Part 2)

\displaystyle (-0.179, -0.178) \cup (-0.010, 0.012)

Step-by-step explanation:

Part 1)

The linear approximation <em>L</em> for a function <em>f</em> at the point <em>x</em> = <em>a</em> is given by:

\displaystyle L \approx f'(a)(x-a) + f(a)

We want to verify that the expression:

1-36x

Is the linear approximation for the function:

\displaystyle f(x) = \frac{1}{(1+9x)^4}

At <em>x</em> = 0.

So, find f'(x). We can use the chain rule:

\displaystyle f'(x) = -4(1+9x)^{-4-1}\cdot (9)

Simplify. Hence:

\displaystyle f'(x) = -\frac{36}{(1+9x)^{5}}

Then the slope of the linear approximation at <em>x</em> = 0 will be:

\displaystyle f'(1) = -\frac{36}{(1+9(0))^5} = -36

And the value of the function at <em>x</em> = 0 is:

\displaystyle f(0) = \frac{1}{(1+9(0))^4} = 1

Thus, the linear approximation will be:

\displaystyle L = (-36)(x-(0)) + 1 = 1 - 36x

Hence verified.

Part B)

We want to determine the values of <em>x</em> for which the linear approximation <em>L</em> is accurate to within 0.1.

In other words:

\displaystyle \left| f(x) - L(x) \right | \leq 0.1

By definition:

\displaystyle -0.1\leq f(x) - L(x) \leq 0.1

Therefore:

\displaystyle -0.1 \leq \left(\frac{1}{(1+9x)^4} \right) - (1-36x) \leq 0.1

We can solve this by using a graphing calculator. Please refer to the graph shown below.

We can see that the inequality is true (i.e. the graph is between <em>y</em> = 0.1 and <em>y</em> = -0.1) for <em>x</em> values between -0.179 and -0.178 as well as -0.010 and 0.012.

In interval notation:

\displaystyle (-0.179, -0.178) \cup (-0.010, 0.012)

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