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1 year ago

PLZ HELP, GIVING BRAINLIEST!!

Chemistry

1 answer:

Pani-rosa [81]1 year ago

6 0

Answer:

C. 2.000 M C6H12O6

Explanation:

Let us obtain the molarity of the solution.

Molar Mass of C6H12O6 = (12x6) + (12x1) + (16x6) = 72 + 12 + 96 = 180g/mol

Mass of C6H12O6 = 180g

Number of mole = Mass /Molar Mass

Number of mole of C6H12O6 = 180/180 = 1mole

Volume = 500mL = 500/1000 = 0.5L

Molarity = mole /Volume

Molarity = 1/0.5

Molarity = 2M

So the solution will be best labelled as 2M C6H12O6

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Answer is: 100 mL of sodium hydroxide.
Chemical reaction: 3NaOH + H₃PO₄ → Na₃PO₄ + 3H₂O.
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n(H₃PO₄) = V(H₃PO₄) · c(H₃PO₄).
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2 years ago

In the nuclear transmutation, 168O (?, α)137N, what is the bombarding particle? In the nuclear transmutation, O (?, )N, what is

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Answer:

The bombarding particle is a Proton

Explanation:

A Nuclear transmutation reaction occurs when radioactive element decay, usually converting them from one element/isotope into another element. Transmutation is the process which causes decay, generally, alpha or beta.

¹⁶₈O(P,alpha) ¹³₇N, can be written as

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16 + x = 13 + 4

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2 years ago

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Answer:

$V_{CO_2}=1.55x10^{5}LCO_2=155m^3CO_2$

Explanation:

Hello,

In this case, given the reaction:

$2 C_8H_{18}(l) + 25 O_2(g)\rightarrow 16 CO_2(g) + 18 H_2O(g)$

The total consumed gallons are computed by considering 686 miles were driven and the consumption is 21.2 miles per gallon, thus:

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Hence, with the given density, one could compute the consumed grams and consequently moles of gasoline as well as moles that were consumed:

$n_{C_8H_{18}}=32.4gal*\frac{3785.41cm^3}{1gal} *\frac{0.805g}{1cm^3} *\frac{1mol}{114g}=864.95mol C_8H_{18}$

Next, since gasoline (molar mass = 114 is in a 2:16 molar relationship with the yielded carbon dioxide, we compute its produced moles as shown below:

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Finally, we could assume the given STP conditions to compute the volume of carbon dioxide, as no more information regarding the space wherein the carbon dioxide is available:

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