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creativ13 [48]
2 years ago
6

How many grams of Cl2 will be produced along with 250.0 kJ of heat in the following reaction? PCl5(g) + 87.9 kJ PCl3(g) + Cl2(g)

Chemistry
2 answers:
Serjik [45]2 years ago
5 0

As per the given chemical equation, 1 mole of Cl₂ is formed when 87.9 kJ of heat is absorbed.

Therefore, 250.0 kJ of heat will yield

\frac{1 mol Cl2}{87.9 kJ } \\  x 250.0 kJ = 2.84 mol Cl₂

Molar mass of mol Cl₂ = 71 g /mol

Mass of Cl₂ =2.84 mol Cl₂ x 71 g /mol = 201.64 g

201.64 g of Cl₂ will be produced along with 250.0 kJ of heat in the given reaction.

AfilCa [17]2 years ago
3 0
250 kJ/87.9 KJ per mole Cl2 * 71g/mole= 202 g It is D for plato users
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6K + B2O3 → 3K2O + 2B
atroni [7]

Answer:

104.84 moles

Explanation:

Given data:

Moles of Boron produced = ?

Mass of B₂O₃ = 3650 g

Solution:

Chemical equation:

6K + B₂O₃    →    3K₂O + 2B

Number of moles of B₂O₃:

Number of moles = mass/ molar mass

Number of moles = 3650 g/ 69.63 g/mol

Number of moles = 52.42 mol

Now we will compare the moles of  B₂O₃ with B from balance chemical equation:

                 B₂O₃          :          B

                    1              :          2

                52.42         :        2×52.42 = 104.84

Thus from 3650 g of  B₂O₃  104.84 moles of boron will produced.

6 0
2 years ago
A molecule contains 23.24 g iodine (I),
gavmur [86]
Convert each amount of grams into moles:

I: 23.24g x 1 mol / 126.90g = 0.1831 mol I

C: 2.198 x 1 mol / 12.01g = 0.1830 mol C

N: 2.562 x 1 mol / 14.01g = 0.1829 mol N

Each element has roughly the same amount of moles, which means the whole number ratio between the elements is 1:1:1

Therefore the empirical formula is ICN
7 0
1 year ago
What mass (g) of barium iodide is contained in 188 ml of a barium iodide solution that has an iodide ion concentration of 0.532m
Katarina [22]

Answer:

What mass (g) of barium iodide is contained in 188 mL of a barium iodide solution that has an iodide ion concentration of 0.532 M?

A) 19.6

B) 39.1

C) 19,600

D) 39,100

E) 276

The correct answer to the question is

B) 39.1  grams

Explanation:

To solve the question

The molarity ratio is given by

188 ml of 0.532 M solution of iodide.

Therefore we have number of moles = 0.188 × 0.532 M = 0.100016 Moles

To find the mass, we note that the Number of moles = \frac{Mass}{Molar Mass} from which we have

Mass = Number of moles × molar mass

Where the molar mass of Barium Iodide = 391.136 g/mol

= 0.100016 moles ×391.136 g/mol = 39.12 g

8 0
1 year ago
Assume the atomic mass of element X is 22.99 amu. A 17.15−g sample of X combines with 14.17 g of another element Y to form a com
Alenkasestr [34]
The formula of the compound is XY. This means that the relation between the moles is 1: 1. One mole of X per one mole of Y.

From the information about the element X you can determine the number of moles of X (which is the same that the number of moles of Y).

# of moles of X = weigth of X / atomic mass of X = 17.15 g / 22.9 g/mol = 0.74598

Now the atomic mass of Y = weight of Y / # of moles of Y = 14.17 g / 0.74598 mol = 19 amu
8 0
1 year ago
Ethene is a useful substance that can form polymers. It has a melting point of 169°C and a boiling point of 104°C. At which temp
blondinia [14]

Answer:

-169°C to -104°C

Explanation:

Ethene, also known as ethylene exists in solid, liquid and gaseous states. Ethene is an aliens with condensed structural formula C2H4. Athens is a colourless gas. It is flammable and is also a sweet smelling gas in its pure form. It is the monomer in the production of polyethylene which is of great importance in the plastic industry. In agriculture, it is used to induce the ripening of fruits. It can be hydrated in order to produce ethanol.

The liquid range of ethene refers to the temperatures at which ethene is found in the liquid state of matter. It is actually the difference between the melting point and the boiling points of ethene. Hence the liquid range of ethene is -169°C to -104°C

4 0
2 years ago
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