Answer:
The function is ![f(x) = 4(\sqrt[3]{16} )^{2x}](https://tex.z-dn.net/?f=f%28x%29%20%3D%204%28%5Csqrt%5B3%5D%7B16%7D%20%29%5E%7B2x%7D)
.
Step-by-step explanation:
We have to choose from options the exponential function which has a simplified base of 4∛4 i.e. ∛(256).
Now, the exponential function in the option III will be the answer.
The function is .
So, the base is ![(\sqrt[3]{16} )^{2}](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7B16%7D%20%29%5E%7B2%7D)
= ![\sqrt[3]{16^{2}} = \sqrt[3]{256} = 4\sqrt[3]{4}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B16%5E%7B2%7D%7D%20%3D%20%5Csqrt%5B3%5D%7B256%7D%20%3D%204%5Csqrt%5B3%5D%7B4%7D)
. (Answer)
The general formula of an exponential function is 
, where b is called the base of the function.
Answer:
6
Step-by-step explanation: 31.50 devided by 5.25 = 6
Answer:
a. The sample has more than 30 grade-point averages.
Step-by-step explanation:
Given that a researcher collects a simple random sample of grade-point averages of statistics students, and she calculates the mean of this sample
We are asked to find the conditions under which that sample mean can be treated as a value from a population having a normal distribution
Recall central limit theorem here
The central limit theorem states that the mean of all sample means will follow a normal distribution irrespective of the original distribution to which the data belonged to provided that
i) the samples are drawn at random
ii) The sample size should be atleast 30
Hence here we find that the correct conditions is a.
Only option a is right
a. The sample has more than 30 grade-point averages.
The given polynomial is 21x⁴ + 3y - 6x² + 34
We want to subtract a polynomial, f(x) so that
21x⁴ + 3y - 6x² + 34 - f(x) = 29x² - 7
Therefore
-f(x) = 29x² - 7 - (21x⁴ + 3y - 6x² + 34)
= -21x⁴ + 35x² - 3y - 41
Answer: 21x⁴ - 35x² + 3y + 41
No
If two planes intersect each other, the intersection will always be a line. where r 0 r_0 r0 is a point on the line and v is the vector result of the cross product of the normal vectors of the two planes.
