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blondinia [14]
2 years ago
12

The box plots show the average gas mileage, in miles per gallon, of the cars sold at a dealership in June and in December.

Mathematics
2 answers:
icang [17]2 years ago
7 0

Answer:

B. The interquartile range for cars is about 7 mpg, and the interquartile range for minivans is about 3 mpg.

Step-by-step explanation:

Montano1993 [528]2 years ago
5 0

Answer:

The correct answer is B The interquartile range for cars is about 7 mpg, and the interquartile range for minivans is about 3 mpg.

Step-by-step explanation: it makes sence and if youre using edge it is correct :)

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Which system of equations can you use to find the roots of the equation 2x3 + 4x2 – x + 5 = –3x2 + 4x + 9? y = 2x3 + x2 + 3x +5
Alona [7]

Answer:The answer is y = 2x3 + 4x2 – x + 5 and  y = –3x2 + 4x + 9

Roots are both: x=-4, x= -1/2 , x= 1

Proof:

Solve for x over the real numbers:

2 x^3 + 4 x^2 - x + 5 = -3 x^2 + 4 x + 9

Subtract -3 x^2 + 4 x + 9 from both sides:

2 x^3 + 7 x^2 - 5 x - 4 = 0

The left hand side factors into a product with three terms:

(x - 1) (x + 4) (2 x + 1) = 0

Split into three equations:

x - 1 = 0 or x + 4 = 0 or 2 x + 1 = 0

Add 1 to both sides:

x = 1 or x + 4 = 0 or 2 x + 1 = 0

Subtract 4 from both sides:

x = 1 or x = -4 or 2 x + 1 = 0

Subtract 1 from both sides:

x = 1 or x = -4 or 2 x = -1

Divide both sides by 2:

Answer:  x = 1 or x = -4 or x = -1/2

Step-by-step explanation:

4 0
1 year ago
Read 2 more answers
If an intravenous solution containing 123 mg of a drug substance in each 250-mL bottle is to be administered at the rate of 200
12345 [234]

Answer:

24.39mL of the solution would be given per hour.

Step-by-step explanation:

This problem can be solved by direct rule of three, in which there are a direct relationship between the measures, which means that the rule of three is a cross multiplication.

The first step to solve this problem is to see how many mg of the solution is administered per hour.

Each minute, 200 ug are administered. 1mg has 1000ug, so

1mg - 1000 ug

xmg - 200 ug

1000x = 200

x = \frac{200}{1000}

x = 0.2mg

In each minute, 0.2 mg are administered. Each hour has 60 minutes. How many mg are administered in 60 minutes?

1 minute - 0.2 mg

60 minutes - x mg

x = 60*0.2

x = 12mg

In an hour, 12 mg of the drug is administered. In 250 mL, there is 123 mg of the drug. How many ml are there in 12 mg of the drug.

123mg - 250mL

12 mg - xmL

123x = 250*12

x = \frac{250*12}{123}

x = 24.39mL

24.39mL of the solution would be given per hour.

7 0
1 year ago
In the diagram, the radius of the outer circle is 2x cm and the radius of the inside circle is 6 cm. The area of the shaded regi
Minchanka [31]
The picture in the attached figure

we know that
Area of circle=pi*r²
area of the shaded region=364*pi cm²
area of the shaded region=area of the outer circle -area of the<span> inside circle

</span>area of the outer circle=pi*[2x]²----> 4*x²*pi cm²
area of the inside circle=pi*6²------> 36*pi cm²
364*pi=4*x²*pi-36*pi------> 364=4*x²-36
4*x²=364+36-----> 4*x²=400
x²=400/4----> x²=100
x=10 cm

the answer is
x=10 cm

4 0
1 year ago
A company produces and sells 211,600 boxes of t-shirts each year. Each production run has a fixed cost of $400 and an additional
Illusion [34]

Answer:x=46

Step-by-step explanation:

Given

Company Produces and sells 211600 boxes of T-shirt each year

Fixed cost =$ 400

Additional cost = $ 3 per box

storage cost =$ 2

let x be the no of production run

therefore

Holding cost per year =holding\ cost\times average\ holding\ items=2\times \frac{211600}{2x}=\frac{211600}{x}

Yearly\ ordering\ cost=cost\ during\ each\ order\times number\ of\ order\ Placed\ per\ year

yearly ordering cost=400x+3\times \frac{211600}{x}

Total cost C(x)=\frac{211600}{x}+400x+3\times \frac{211600}{x}

differentiate C(x) w.r.t to x we get

\frac{\mathrm{d} C(x)}{\mathrm{d} x}=400-\frac{3\times 211600}{x^2}-\frac{1}{211600}

Put \frac{\mathrm{d} C(x)}{\mathrm{d} x}=0 to get max/min value

400-\frac{211600}{x^2}-\frac{3\times 211600}{x^2}=0

x^2=\frac{211600}{100}

x=\sqrt{2116}

x=46

therefore 46 runs must be performed

5 0
1 year ago
Nathan flew 3,547 miles from Canada to California during the first part of his trip. He flew 2,567 miles from California to Hawa
AURORKA [14]

Difference in the number of miles Nathan flew between the first and second parts of his trip is 980 miles

<em><u>Solution:</u></em>

Given that Nathan flew 3,547 miles from Canada to California during the first part of his trip

He flew 2,567 miles from California to Hawaii during the second part of his trip

Therefore,

first part of his trip = 3547 miles

second part of his trip = 2567 miles

Difference in the number of miles Nathan flew between the first and second parts of his trip is given as:

difference = first part of his trip - second part of his trip

difference = 3547 - 2567 = 980

Therefore, the difference in number is 980 miles

4 0
2 years ago
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