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Stella [2.4K]
2 years ago
6

Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to Volume of bucket= ½ ft3 Weight of empty bucket 20.

3 lb Weight of bucket filled with dry rodded coarse aggregate 69.6 Ib determine its unit weight. The following data are obtained: a. Calculate the dry-rodded unit weight If the bulk dry specific gravity of the aggregate is 2.620, calculate the percent voids between aggregate particles.

Engineering
1 answer:
Darina [25.2K]2 years ago
3 0

Answer: a) 98.6lb/ft^3

b) 60%

Explanation: The Dry-Rodded Unit Weight of an aggregate is the weight required to fill a contained or a specified unit volume, after it has been rodded to attain maximum packing.

Please find the attached file for the solution

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A three-story school has interior column bays that are spaced 25 ft apart in both directions. If the loading on the flat roof is
Lady_Fox [76]

Answer:

Explanation:

Floor Load:

Lo= 50psf

At= 25x25 = 625 square feet

L= Lo(0.25 +15/\sqrt{KuAt)}

L=50(0.25+15/\sqrt{(4)(625)}= 13.1psf

%reduction= 13.1/50 = 26%

Fr= 3[(13.1psf)(25ft)(25ft)+(20psf)(25ft)(25ft)]= 62k

7 0
2 years ago
The velocity distribution for laminar flow between parallel plates is given by u umax = 1 − ( 2y h ) 2 Where h is the distance s
Lynna [10]

Answer:

Explanation:

For we to calculate the shear stress on the upper plate and give its direction. Sketch the variation of shear stress across the channel, I used hand in solving it, check attached file below

5 0
2 years ago
On the reality television show "Survivor," two tribes compete for luxuries such as food and shelter. During such challenges, one
Ivan

Answer:

Realistic Group Conflict Theory

Explanation:

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These groups may compete for a scarce resources based on reality or perception.

These conflicts may be over political power, capital, or social status, etc.

According to this theory, in the competition, only one group wins over the scarce resources while the other has to lose.

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5 0
2 years ago
Six years ago, an 80-kW diesel electric set cost $160,000. The cost index for this class of equipment six years ago was 187 and
exis [7]

Answer:

new boiler total cost = $229706.825

new boiler total cost = $127512

Explanation:

given data

power p1 = 80 kW

cost C = $160000

cost index CI 1 = 187

cost index CI 2= 194

cost capacity factor f = 0.6

power p2 = 120 kW

current cost = $18000

to find out

total cost and cost of 40 kW

solution

we consider here CN cost for new boiler and CO cost for old boiler

and x is capacity of new boiler

first we find old boiler current cost that is

current cost CO = C × \frac{CI 1 }{CI 2 }   .............1

put here value

current cost = 160000 × \frac{194 }{187 }

new current cost = $165989.304

and

use here power sizing technique for 124 kW

CN/CO = (\frac{p2}{p1} )^{f}    ...............2

put here value and find CN

CN/CO = (\frac{p2}{p1} )^{f}  

CN / 165989.304 = (\frac{120}{80} )^{0.6}  

CN = 211706.825

so new cost = $211706.825

so

total cost for new boiler is

total cost = new cost + current cost

total cost = 211706.825 + 18000

new boiler total cost = $229706.825

and

for 40 kW new cost will be

use equation 2

CN/CO = (\frac{p2}{p1} )^{f}

CN / 165989.304 = (\frac{40}{80} )^{0.6}  

CN = 109512

so new cost is $109512

so

total cost for new boiler is

total cost = new cost + current cost

total cost = 109512 + 18000

new boiler total cost = $127512

7 0
2 years ago
. A piston-cylinder device whose piston is resting on top of a set of stops initially contains 0.5 kg of helium gas at 100 kPa a
Delvig [45]

Answer:

Qin = 1857 kJ

Explanation:

Given

m = 0.5 Kg

T₁ = 25°C = (25 + 273) K = 298 K

P₁ = 100 kPa

P₂ = 500 kPa

First, the temperature when the piston starts rising is determined from the ideal gas equations at the initial state and at that state:

T₂ = T₁*P₂/P₁

⇒  T₂ = 298 K*(500 kPa/100 kPa) = 1490 K

Until the piston starts rising no work is done so the heat transfer is the change in internal energy

Qin = ΔU = m*cv*(T₂-T₁)

⇒   Qin = 0.5*3.1156*(1490 - 298) kJ = 1857 kJ

8 0
2 years ago
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