The velocity distribution for laminar flow between parallel plates is given by u umax = 1 − ( 2y h ) 2 Where h is the distance s
eparating the plates and the origin is placed midway between the plates. Consider a flow of water at 150C, with umax = 0.10 m ∕ s and h = 0.1mm. Calculate the shear stress on the upper plate and give its direction. Sketch the variation of shear stress across the channel.
1 answer:
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Answer:
Option (d) 2 min/veh
Explanation:
Data provided in the question:
Average time required = 60 seconds
Therefore,
The maximum capacity that can be accommodated on the system, μ = 60 veh/hr
Average Arrival rate, λ = 30 vehicles per hour
Now,
The average time spent by the vehicle is given as
⇒
thus,
on substituting the respective values, we get
Average time spent by the vehicle =
or
Average time spent by the vehicle =
or
Average time spent by the vehicle =
or
Average time spent by the vehicle = hr/veh
or
Average time spent by the vehicle = min/veh
[ 1 hour = 60 minutes]
thus,
Average time spent by the vehicle = 2 min/veh
Hence,
Option (d) 2 min/veh
To resolve this problem we have,
is unknown.
With these dates we can calculate the Flexural strenght of the specimen,
After that, we can calculate the flexural strenght for the square cross section using the previously value.