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Xelga [282]
2 years ago
11

A pipe is insulated such that the outer radius of the insulation is less than the critical radius. Now the insulation is taken o

ff. Will the rate of heat transfer from the pipe increase or decrease for the same pipe surface temperature?
Engineering
1 answer:
irina [24]2 years ago
7 0

Answer:

the heat transfer from the pipe will decrease when the insulation is taken off for r₂< r_{cr}

where;

r₂ = outer radius

r_{cr} = critical radius

Explanation:

Note that the critical radius of insulation depends on the thermal conductivity of the insulation k and the external convection heat transfer coefficient h .

r_{cr} =\frac{k}{h}

The rate of heat transfer from the cylinder increases with the addition of insulation for outer radius less than  critical radius (r₂< r_{cr}) 0,  and reaches a maximum when r₂ = r_{cr}, and starts to decrease for r₂< r_{cr}. Thus, insulating the pipe may actually increase the rate of heat transfer from the pipe instead of decreasing it when r₂< r_{cr} .

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What is the linear distance traveled in one revolution of a 36-inch wheel
Afina-wow [57]

Answer:

  36π inches ≈ 113.0973 inches

Explanation:

The circumference of the wheel is pi times its diameter.

  C = πd

  C = π(36 in) = 36π in ≈ 113.0973 in

The distance around the wheel is 36π inches, about 113.0973 inches.

7 0
2 years ago
Why is it so dangerous to use a ground lift on a metal cased power tool
MaRussiya [10]
Answer:

Removal of the safety ground connection on equipment can expose users to an increased danger of electric shock and may contradict wiring regulations. ... If a fault develops in any line-operated equipment, cable shields and equipment enclosures may become energized, creating an electric shock hazard.
7 0
1 year ago
Radioactive wastes are temporarily stored in a spherical container, the center of which is buried a distance of 10 m below the e
puteri [66]

Given:

outer radius, R' = 10 m

inner diameter, d = 2 m

inner radius, R = \frac{d}{2} = 1 m

surface temperature, T' = 20^{\circ}C

Thermal conductivity of soil, K = 0.52 W/mK

Solution:

To calculate the thermal temperature of conductor, T, we know amount of heat, Q is given by :

Q =  \frac{T - T'}{\frac{R' - R}{4\pi KRR'}}

500 =  (T - 20)\frac{4\pi \times0.52\times 1\times 10}{10 - 1}

T = 68.86 +20 = 88.865^{\circ}C  

Therefore, outside surface temperature is 88.865^{\circ}C  

4 0
2 years ago
what is the advantage of decreasing the field current of a separately excited dc motor below its nominal value
enyata [817]

Answer:

Ability to rotate at higher speeds

Explanation:

Constant K1 becomes greater than the other constant K2

This translates to that the motor being able to rotate at high speeds, without necessarily exceeding the nominal armature voltage.

The armature voltage is the voltage that is developed around the terminals of the armature winding of an Alternating Current, i.e AC or a Direct Current, i.e DC machine during the period in which it tries to generate power.

6 0
2 years ago
Six years ago, an 80-kW diesel electric set cost $160,000. The cost index for this class of equipment six years ago was 187 and
exis [7]

Answer:

new boiler total cost = $229706.825

new boiler total cost = $127512

Explanation:

given data

power p1 = 80 kW

cost C = $160000

cost index CI 1 = 187

cost index CI 2= 194

cost capacity factor f = 0.6

power p2 = 120 kW

current cost = $18000

to find out

total cost and cost of 40 kW

solution

we consider here CN cost for new boiler and CO cost for old boiler

and x is capacity of new boiler

first we find old boiler current cost that is

current cost CO = C × \frac{CI 1 }{CI 2 }   .............1

put here value

current cost = 160000 × \frac{194 }{187 }

new current cost = $165989.304

and

use here power sizing technique for 124 kW

CN/CO = (\frac{p2}{p1} )^{f}    ...............2

put here value and find CN

CN/CO = (\frac{p2}{p1} )^{f}  

CN / 165989.304 = (\frac{120}{80} )^{0.6}  

CN = 211706.825

so new cost = $211706.825

so

total cost for new boiler is

total cost = new cost + current cost

total cost = 211706.825 + 18000

new boiler total cost = $229706.825

and

for 40 kW new cost will be

use equation 2

CN/CO = (\frac{p2}{p1} )^{f}

CN / 165989.304 = (\frac{40}{80} )^{0.6}  

CN = 109512

so new cost is $109512

so

total cost for new boiler is

total cost = new cost + current cost

total cost = 109512 + 18000

new boiler total cost = $127512

7 0
2 years ago
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