Answer:
C) The auditor may or may not achieve the desired risk of assessing control risk too low.
Step-by-step explanation:
In a concept of risk sampling, if the sample size is chosen randomly in accordance with random selection procedures, the auditor may or may not achieve the desired risk of assessing risk too low. In other words the auditor may or may not achieve desired precision. This is because a samole chosen randomly may not represent the true population.
This depends largely on the sample size. If the sample size selected is too small, the allowance for sampling risk will be larger than what is required because it will lead to a large standard error of the mean
Answer:
The confidence interval for the difference in proportions is

No. As the 95% CI include both negative and positive values, no proportion is significantly different from the other to conclude there is a difference between them.
Step-by-step explanation:
We have to construct a confidence interval for the difference of proportions.
The difference in the sample proportions is:

The estimated standard error is:

The z-value for a 95% confidence interval is z=1.96.
Then, the lower and upper bounds are:

The confidence interval for the difference in proportions is

<em>Can it be concluded that there is a difference in the proportion of drivers who wear a seat belt at all times based on age group?</em>
No. It can not be concluded that there is a difference in the proportion of drivers who wear a seat belt at all times based on age group, as the confidence interval include both positive and negative values.
This means that we are not confident that the actual difference of proportions is positive or negative. No proportion is significantly different from the other to conclude there is a difference.
Answer:

Step-by-step explanation:
we have

we know that
The formula to solve a quadratic equation of the form
is equal to
in this problem we have
so
substitute in the formula

therefore
StartFraction 19 minus StartRoot 365 EndRoot Over 2 EndFraction comma StartFraction 19 + StartRoot 365 EndRoot Over 2 EndFraction
Answer:
<h2> 105 tickets</h2>
Step-by-step explanation:
To solve this problem we need to model an equation to represent the situation first.
the goal is to archive $7500 in the even, bearing in mind that there is a cost of $375 fee for rent, we need to put this amount into consideration
let the number of tickets be x
so
75x-375>=7500--------1
Equation 1 above is a good model for the equation
we can now solve for x to determine the number of tickets to be sold to archive the aim
75x-375>=7500--------1
75x>=7500+375
75x>=7875
divide both sides by 75 we have
x>=7875/75
x>=105 tickets
so they must sell a total of 105 tickets and above to meet the target of $7500 with the rent inclusive
x-4=x(2)
x-4=2x
+4 +4
8 = 6
lilly has 8 stamps and mackenzie has 6