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ad-work [718]
2 years ago
8

four seniors and six juniors are competing for four places on a quiz bowl team. what is the approximate probability that all fou

r seniors will be chosen at random ?
Mathematics
2 answers:
12345 [234]2 years ago
6 0
The answer is 4 out of 10
uranmaximum [27]2 years ago
3 0

Answer:

The probability is:

                      4/10

Step-by-step explanation:

We are given:

four seniors and six juniors.

Number of seniors=4

Total number of people=10 ( since 6+4=10)

We are asked to fill four places on a quiz bowl team.

We are asked to find the probability that all four seniors will be chosen at random.

The probability is calculated as:

Ratio of the number of seniors to the total number of people.

            Hence, the probability is:

                                4/10

                       

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If the size of the sample to be used in a particular test of attributes has not been determined by utilizing statistical concept
EleoNora [17]

Answer:

C) The auditor may or may not achieve the desired risk of assessing control risk too low.

Step-by-step explanation:

In a concept of risk sampling, if the sample size is chosen randomly in accordance with random selection procedures, the auditor may or may not achieve the desired risk of assessing risk too low. In other words the auditor may or may not achieve desired precision. This is because a samole chosen randomly may not represent the true population.

This depends largely on the sample size. If the sample size selected is too small, the allowance for sampling risk will be larger than what is required because it will lead to a large standard error of the mean

5 0
2 years ago
A car insurance company suspects that the younger the driver is, the more reckless a driver he/she is. They take a survey and gr
erastovalidia [21]

Answer:

The confidence interval for the difference in proportions is

-0.028\leq p_1-p_2 \leq 0.096

No. As the 95% CI include both negative and positive values, no proportion is significantly different from the other to conclude there is a difference between them.

Step-by-step explanation:

We have to construct a confidence interval for the difference of proportions.

The difference in the sample proportions is:

p_1-p_2=x_1/n_1-x_2/n_2=(183/217)-(322/398)=0.843-0.809\\\\p_1-p_2=0.034

The estimated standard error is:

\sigma_{p_1-p_2}=\sqrt{\frac{p_1(1-p_1)}{n_1}+\frac{p_2(1-p_2)}{n_2} } \\\\\sigma_{p_1-p_2}=\sqrt{\frac{0.843*0.157}{217}+\frac{0.809*0.191}{398} } \\\\\sigma_{p_1-p_2}=\sqrt{0.000609912+0.000388239}=\sqrt{0.000998151} \\\\ \sigma_{p_1-p_2}=0.0316

The z-value for a 95% confidence interval is z=1.96.

Then, the lower and upper bounds are:

LL=(p_1-p_2)-z*\sigma_p=0.034-1.96*0.0316=0.034-0.062=-0.028\\\\\\UL=(p_1-p_2)+z*\sigma_p=0.034+1.96*0.0316=0.034+0.062=0.096

The confidence interval for the difference in proportions is

-0.028\leq p_1-p_2 \leq 0.096

<em>Can it be concluded that there is a difference in the proportion of drivers who wear a seat belt at all times based on age group?</em>

No. It can not be concluded that there is a difference in the proportion of drivers who wear a seat belt at all times based on age group, as the confidence interval include both positive and negative values.

This means that we are not confident that the actual difference of proportions is positive or negative. No proportion is significantly different from the other to conclude there is a difference.

8 0
2 years ago
Which are the solutions of x2 = 19x + 1?
Finger [1]

Answer:

(\frac{19-\sqrt{365}} {2},\frac{19+\sqrt{365}} {2})

Step-by-step explanation:

we have

x^2=19x+1

we know that

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-x^{2}-19x-1=0  

so

a=1\\b=-19\\c=-1

substitute in the formula

x=\frac{-(-19)\pm\sqrt{-19^{2}-4(1)(-1)}} {2(1)}

x=\frac{19\pm\sqrt{365}} {2}

x=\frac{19+\sqrt{365}} {2}

x=\frac{19-\sqrt{365}} {2}

(\frac{19-\sqrt{365}} {2},\frac{19+\sqrt{365}} {2})

therefore

StartFraction 19 minus StartRoot 365 EndRoot Over 2 EndFraction comma StartFraction 19 + StartRoot 365 EndRoot Over 2 EndFraction

6 0
2 years ago
Read 2 more answers
The Sweet water High School Project Graduation committee is hosting a dinner-and-dance fundraiser at the Sweet water Community C
yan [13]

Answer:

<h2> 105 tickets</h2>

Step-by-step explanation:

To solve this problem we need to model an equation to represent the situation first.

the goal is to archive $7500 in the even, bearing in mind that there is a cost of $375 fee for rent, we need to put this amount into consideration

let the number of tickets be x

so

75x-375>=7500--------1

Equation 1 above is a good model for the equation

we can now solve for x to determine the number of tickets to be sold to archive the aim

75x-375>=7500--------1

75x>=7500+375

75x>=7875

divide both sides by 75 we have

x>=7875/75

x>=105 tickets

so they must sell a total of 105 tickets and above to meet the target of $7500 with the rent inclusive

4 0
2 years ago
Read 2 more answers
Lily and Mackenzie collected some stamps. If Lily gave 4 stamps to Mackenzie, Mackenzie would have twice as many stamps as Lily.
vlabodo [156]

x-4=x(2)

x-4=2x

+4   +4

8 = 6

lilly has 8 stamps and mackenzie has 6

7 0
2 years ago
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