Ask question

Ask question

All categories

2 years ago

4

A total charge of 100. coulombs flows past a fixed point in a circuit every 500. seconds. What is the current at this point in t

he circuit?

1 answer:

Sindrei [870]2 years ago

4 0

Answer:

0.200 A

Explanation:

Current is the rate of change of charge, or Coulombs per second.

I = Q/t

I = (100. C) / (500. s)

I = 0.200 A

You might be interested in

A policeman starts giving chase 60 seconds after a stolen car zooms by at 108 km/hr. At what minimum speed should he drive if he

Iteru [2.4K]

Answer:

30.93 m/s

Explanation:

Given that, the speed of stolen car is,

$v_{s} =108km/hr\\v_{s} =108\times \frac{5}{18}m/s\\ v_{s} =30m/s$

As policeman start chasing the stolen car after 60 seconds.

Now suppose the speed of policeman car is, $v_{p}$

The policeman catches the stolen car at a distance of,

$S=60km\\S=60000m$

Now the distance covered by the policeman in time t is $v_{p}\times t$

And the distane cover by the thief in stolen car in time(t+60s) is $v_{s}\times (t+60sec)$ .

And these distances are equal and they are equal to 60000 m.

Therefore,

$v_{p}\times t=v_{s}\times (t+60sec)=60000m$

Therfore,

$v_{s}\times (t+60sec)=60000m\\30m/s\times (t+60sec)=60000m\\(t+60s)=2000s\\t=1940s$

Now use this value to solve for minimum speed of policeman's car.

$v_{p}\times 1940=60000\\v_{p}=30.93 m/s$

Therefore minimum speed of policeman's car is 30.93 m/s.

6 0

2 years ago

Jason wanted to find the Volume of two rocks How could you use the tools below that is shown to find the volume of these irregul

Marta_Voda [28]

I think the answer is to measure the tubes

5 0

2 years ago

Read 2 more answers

Gregor Mendel finished his pea plant experiments in 1863 and published his results in 1866. However, few scientists saw Mendel's

gregori [183]

Answer:

it would be Individuals get one factor for a trait from each parent. and dominant factor can hide the expression of a recessive factor when both are present.

8 0

2 years ago

Calculate the distance d from the center of the sun at which a particle experiences equal attractions from the earth and the sun

fredd [130]

Answer:

149.34 Giga meter is the distance d from the center of the sun at which a particle experiences equal attractions from the earth and the sun.

Explanation:

Mass of earth = m = $5.976\times 10^{24} kg$

Mass of Sun = M = 333,000 m

Distance between Earth and Sun = r = 149.6 gm = 1.496\times 10^{11} m[/tex]

1 giga meter = $10^{9} meter$

Let the mass of the particle be m' which x distance from Sun.

Distance of the particle from Earth = (r-x)

Force between Sun and particle:

$F=G\frac{M\times m'}{x^2}=G\frac{333,000 m\times m'}{x^2}$

Force between Sun and particle:

$F'=G\frac{mm'}{(r-x)^2}$

Force on particle is equal:

F = F'

$G\frac{333,000 m\times m'}{x^2}=G\frac{mm'}{(r-x)^2}$

$\frac{x}{r-x}=\sqrt{333,000}$ = ±577.06

Case 1:

$\frac{x}{r-x}=577.06$

x = $1.49\times 10^{11} m=149.34 Gm$

Acceptable as the particle will lie in between the straight line joining Earth and Sun.

Case 2:

$\frac{x}{r-x}=-577.06$

x = $1.49\times 10^{11} m=149.86 Gm$

Not acceptable as the particle will lie beyond on line extending straight from the Earth and Sun.

3 0

2 years ago

This version of Einstein’s equation is often used directly to find what value?

Setler [38]

This version of Einstein’s equation is often used directly to find what value? E = ∆mc2

Answer: This version of Einstein’s equation is often used directly to find the mass that is lost in a fusion reaction. Therefore the correct answer to this question is answer choice C).

I hope it helps, Regards.

8 0

2 years ago

Read 2 more answers