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valentinak56 [21]
2 years ago
5

If the lengths of corresponding altitudes have the same ratio as the length of any pair of corresponding sides, the two triangle

s are similar.
always
sometimes
never
Mathematics
2 answers:
krok68 [10]2 years ago
4 0
Two triangles are similar if all corresponding sides are proportional.

Therefore, if it is given that sides are proportional, then the two triangles are similar.

This property of triangles is consistent and either true or false so sometimes is never an answer.

Since it is true , the answer is Always.
Lelechka [254]2 years ago
3 0

Answer:

answer always

Step-by-step explanation:

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If ∆ABC and ∆GEF are congruent, the value of x is___? and the value of y is ___?
attashe74 [19]

<u>Answer-</u>

<em>The value of y is </em><em>6 units</em><em>.</em>

<u>Solution-</u>

Given ∆ABC ≅ ∆GEF

If two triangles are congruent, then the corresponding sides are also congruent.

So,

EF = BC, GF = AC

Putting the values,

\Rightarrow x-y=4 --------------1

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Putting the values of x in equation 1,

\Rightarrow 10-y=4

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Therefore, the value of y is 6 units.

7 0
2 years ago
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horrorfan [7]

Answer:

a. X\sim N(\mu = 6.1, \sigma = 1.9) b. 6.1 c. 0.6842 d. 0.4166 e. 0.1194 f. 8.5349

Step-by-step explanation:

a. The distribution of X is normal with mean 6.1 kg. and standard deviation 1.9 kg. this because X is the weight of a randomly selected seedless watermelon and we know that the set of weights of seedless watermelons is normally distributed.

b. Because for the normal distribution the mean and the median are the same, we have that the median seedless watermelong weight is 6.1 kg.

c. The z-score for a seedless watermelon weighing 7.4 kg is (7.4-6.1)/1.9 = 0.6842

d. The z-score for 6.5 kg is (6.5-6.1)/1.9 = 0.2105, and the probability we are seeking is P(Z > 0.2105) = 0.4166

e. The z-score related to 6.4 kg is z_{1} = (6.4-6.1)/1.9 = 0.1579 and the z-score related to 7 kg is z_{2} = (7-6.1)/1.9 = 0.4737, we are seeking P(0.1579 < Z < 0.4737) = P(Z < 0.4737) - P(Z < 0.1579) = 0.6821 - 0.5627 = 0.1194

f. The 90th percentile for the standard normal distribution is 1.2815, therefore, the 90th percentile for the given distribution is 6.1 + (1.2815)(1.9) = 8.5349

7 0
2 years ago
Carys is checking her tax bill for the last year.
mariarad [96]
£18240

since the amount she earned falls within the range of the tax rate 40%, multiply her earnings by 0.4.

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2 years ago
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Recently, 18.3% of visitors to the travelocity web site hailed from the google search engine. a random sample of 130 visitors on
kaheart [24]
In your problem:
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The standard error can be calculated by the formula:
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mafiozo [28]

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Step-by-step explanation:

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