A tractor trailer truck carrying boxes of toy rubber ducks stops at a weigh station on the highway. The driver is told that the
2 answers:
Answer:
c. The truck drops off its load of toys, then stops at a second weigh station. Now the truck weighs 33,000 pounds. What is its weight in newtons?
148,500 N
D. Challenge! Find the total mass of the rubber duck filled boxes that were carried by the truck.
4,950kg
Explanation:
First things first, a Newton (N) is so we need to convert pounds into kilograms.
1 pound is 0.45 kg.
So 33,000 pounds is equal to: 33,000*0.45=14,850kg, this right here is actually mass
Now, weight is mass*gravitational acceleration.
Gravitational acceleration is equal to 9.8, but it's usually rounded up to 10
to simplify calculations so:
C. The truck drops off its load of toys, then stops at a second weigh station. Now the truck weighs 33,000 pounds. What is its weight in newtons?
14,850kg * 10= 148,500
= 148,500 N
D. Challenge! Find the total mass of the rubber duck filled boxes that were carried by the truck.
Mass with the load: 44,000 pounds
Mass without the load: 33,000 pounds
Mass of the load = mass with load - mass without = 11,000
Mass of the load in kg = 11,000*0.45=4,950kg
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Explanation:
We have the following data:
The angle at which the water ballon was thrown
The horizontal distance of the water ballon
The acceleration due gravity
We need to find the initial velocity at which the water ballon was thrown, and we can find it by the following equation:
(1)
Where is the total time the water ballon is on air
On the other hand, when we talk about parabolic motion (as in this situation) the water ballon reaches its maximum height just in the middle of this parabola, when and the time
is half the time
it takes the complete parabolic path.
So, if we use the following equation, we will find :
(2)
Isolating :
(3)
Remembering :
(4)
Substituting (4) in (1):
(5)
Isolating :
(6)
(7)
Finally:
The elastic potential energy increases by a factor of 9
Explanation:
The elastic potential energy of a bowstring is given by
(1)
where
k is the spring constant
x is the elongation of the bowstring
Hooke's law states the relationship between the force applied and the elongation of an elastic object:
where
F is the force applied
x is the elongation
We can rewrite it as
And substituting into (1),
In this problem, the force applied to the bowstring is tripled,
F' = 3F
So the final elastic potential energy is:
So, the elastic potential energy increases by a factor of 9.
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Answer:
4.
Explanation:
Given,
frequency of standing wave = 603 Hz
length of string,L = 1.33 m
speed of the wave, v = 402 m/s
number of antinodes = ?
Wavelength of the standing wave
Number of anti nodes in the standing wave
n =3.97= 4.
Number of antinodes is equal to 4.