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lidiya [134]
2 years ago
7

A standing wave of 603 Hz is produced on a string that is 1.33 m long and fixed on both ends. If the speed of the waves on this

string is 402 m/s, how many antinodes are there in the standing wave?
Physics
1 answer:
kondaur [170]2 years ago
7 0

Answer:

4.

Explanation:

Given,

frequency of standing wave = 603 Hz

length of string,L = 1.33 m

speed of the wave, v = 402 m/s

number of antinodes = ?

Wavelength of the standing wave

\lambda = \dfrac{v}{f}

\lambda = \dfrac{402}{603}

\lambda = 0.67\ m

Number of anti nodes in the standing wave

n=\dfrac{l}{\frac{\lambda}{2}}

n=\dfrac{2l}{\lambda}

n=\dfrac{2\times 1.33}{0.67}

n =3.97= 4.

Number of antinodes is equal to 4.

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