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rjkz [21]
2 years ago
8

Two pool balls, each moving at 2 m/s, roll toward each other and collide. Suppose after bouncing apart, each moves at 2 m/s. Thi

s collision violates conservation of
A) Momentum.
B) Energy.
C) Both momentum and energy.
D) None of the above choices.
Physics
1 answer:
stira [4]2 years ago
4 0

Answer:D

Explanation:according to the law of conservation of energy/momentum, when two bodies collides, their total momentum and energy before and after collision are equal. Given that the two bodies move with the same velocities after collision, means that the law has not been violated since momentum = mass x velocity (where mass is constant)

You might be interested in
Your friend says, “chemical changes are caused by an input in energy. In physical changes, there is no transfer of energy” is yo
nalin [4]

Answer:

Ok, let's suppose the simplest of the physical changes:

We have an object that is not moving (so it is not accelerated)

and there is change, now the object moves.

Because there was a change, means that there was an acceleration, and by the second Newton's law.

Force equals mass times acceleration:

F = m*a

There must be a force.

So suppose that you pushed the object, then some energy that you had, you transferred it to the object, that now is moving and now has kinetic energy.

Now, is kinda true that in a closed system the total energy is always constant, but it depends on what is our system.

So if we think in our system as you and the object, then in the whole system the energy does not change because the energy that you lost is now on the object, but again, there was a transfer of energy.

So no, your friend is not correct.

3 0
2 years ago
A 65 kg students is walking on a slackline, a length of webbing stretched between two trees. the line stretches and sags so that
polet [3.4K]

Answer : Tension in the line = 936.7 N

Explanation :

It is given that,

Mass of student, m = 65 kg

The angle between slackline and horizontal, \theta=20^0

The two forces that acts are :

(i) Tension

(ii) Weight

So, from the figure it is clear that :

mg=2T\ sin\ \theta

T=\dfrac{mg}{2\ sin\theta}

T=\dfrac{65\ kg\times 9.8\ m/s^2}{2(sin\ 20)}

T=936.7\ N

Hence, this is the required solution.

5 0
1 year ago
Read 2 more answers
How does end A of the rod react when the charged ball approaches it after a great many previous contacts with end A? Assume that
sleet_krkn [62]

Answer: IT IS STRONGLY REPELLED

Explanation: The laws of guiding magnetic attraction or repulsion of Magnetic materials,states that when like poles are brought together they repel each other, but when unlike poles are brought together they are attracted.

The rod will be strongly repelled because the forces on the rod is greater and has the same Polarity as the charged ball.

6 0
1 year ago
A 1 kg coconut falls vertically from a height of 10 meters. Use the principle of conservation of mechanical
Kay [80]

Answer:

Explanation:

Question 1:

Mass=1kg

Acceleration due to gravity=9.8m/s^2

Height=10m

on the before falling it has potential energy

Potential energy=mass x acceleration due to gravity x height

Potential energy=1 x 9.8 x 10

Potential energy=98 joules

Question 2:

Potential energy=kinetic energy base base on energy transformation

Kinetic energy=(mass x (velocity)^2)➗2

98=(1 x(velocity))^2 ➗ 2

Cross multiplying

98 x 2=(velocity)^2

196=(velocity)^2

Velocity=√(196)

Velocity=14

Velocity=14m/s

5 0
2 years ago
Suppose that we use a heater to boil liquid nitrogen (N2 molecules). 4480 J of heat turns 20 g of liquid nitrogen into gas. Note
love history [14]

Answer:

The energy is 9.4\times10^{-21}\ J

(a) is correct option

Explanation:

Given that,

Energy = 4480 j

Weight of nitrogen = 20 g

Boil temperature = 77 K

Pressure = 1 atm

We need to calculate the internal energy

Using first law of thermodynamics

Q=\Delta U+W

Q=\Delta U+nRT

Put the value into the formula

4480=\Delta U+\dfrac{20}{28}\times8.314\times77

\Delta U=4480-\dfrac{20}{28}\times8.314\times77

\Delta U=4022.73\ J

We need to calculate the number of molecules in 20 g N₂

Using formula of number of molecules

N=n\times \text{Avogadro number}

Put the value into the formula

N=\dfrac{20}{28}\times6.02\times10^{23}

N=4.3\times10^{23}

We need to calculate the energy

Using formula of energy

E=\dfrac{\Delta U}{N}

Put the value into the formula

E=\dfrac{4022.73}{4.3\times10^{23}}

E=9.4\times10^{-21}\ J

Hence, The energy is 9.4\times10^{-21}\ J

4 0
1 year ago
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