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weeeeeb [17]
2 years ago
12

Una masa de 0,5 kg está sobre una pendiente inclinada 20º sujeta mediante una cuerda paralela a la pendiente que impide que desl

ice. Si no hay rozamiento, ¿qué fuerza hace la cuerda?
Physics
1 answer:
jeka942 years ago
4 0

Answer:

<em>4.61 N</em>

<em></em>

Explanation:

masa = 0.5 kg

ángulo de inclinación = 20°

Peso normal de la masa = mg

donde m = masa

g = aceleración debido a la gravedad = 9.81 m/s^2

Peso normal = 0.5 x 9.81 = 4.905 N

Si la masa se mantiene en su lugar mediante una cuerda paralela al plano, y no hay fricción en la masa, entonces

La fuerza sobre la cuerda = peso normal x cos ∅

donde ∅ = 20 °

La fuerza sobre la cuerda = 4.905 x cos 20°

==><em> 4.61 N</em>

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Answer

given,

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length of scaffold = 6 m

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now equating all the vertical forces acting in the system.

T₁ + T₂ = m g + M g

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system is equilibrium so, the moment along the system will also be zero.

taking moment about rope with tension T₂.

now,

T₁ x 6 - mg x (6-1.5) - M g x 3 = 0

'3 m' is used because the weight of the scaffold pass through center of gravity.

6 T₁ = 50 x 9.8 x 4.5 + 70 x 9.8 x 3

6 T₁ = 4263

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T₂ = 1176 - 710.5

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A 57 kg paratrooper falls through the air. How much force is pulling him down?
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