<span>Using Coulomb's law: k*(-0.3)*(-0.3)/(d^2)=19.2
D is the distance between the two negative charges</span>
In a series circuit . . .
-- The total resistance is the sum of the individual resistors.
-- The current is the same at every point in the circuit.
The total resistance in this circuit is (3Ω + 6Ω ) = 9Ω
The current at every point is (V/R) = (12v / 9Ω ) = <em>1.33 A</em> .
Pick choice<em> (a)</em>.
Answer:

Explanation:
As we know that the magnetic field near the center of solenoid is given as

now we know that initially the length of the solenoid is L = 18 cm and N number of turns are wounded on it
So the magnetic field at the center of the solenoid is 2 mT
now we pulled the coils apart and the length of solenoid is increased as L = 21 cm
so we have

now plug in all values in it


Answer:
Magnitude of the force is 2.135N and the direction is 41.8° below negative y-axis
Explanation:
The stiff wire 50.0cm long bent at a right angle in the middle
One section lies along the z axis and the other is along the line y=2x in the xy plane

tan θ = 2
Therefore,
slope m = tan θ = y / x

Then length of each section is 25.0cm
so, length vector of the wire is

And magnetic field is B = (0.318T)i
Therefore,

![\bar F = (20.0)[(0.112m)i +(0.224m)j-(0.250m)k \times 90.318T)i]](https://tex.z-dn.net/?f=%5Cbar%20F%20%3D%20%2820.0%29%5B%280.112m%29i%20%2B%280.224m%29j-%280.250m%29k%20%5Ctimes%2090.318T%29i%5D)
![= (20.0)(i(0)+j(-0.250)(0.318T)+k[0-(0.224m)(0.318T)]\\\\=(20.0)(-0.250)(0.318)j-(20.0)(0.224)(0.318T)\\\\=-(1.59N)j-(1.425N)k](https://tex.z-dn.net/?f=%3D%20%2820.0%29%28i%280%29%2Bj%28-0.250%29%280.318T%29%2Bk%5B0-%280.224m%29%280.318T%29%5D%5C%5C%5C%5C%3D%2820.0%29%28-0.250%29%280.318%29j-%2820.0%29%280.224%29%280.318T%29%5C%5C%5C%5C%3D-%281.59N%29j-%281.425N%29k)
Magnitude of the force is

Direction is

Magnitude of the force is 2.135N and the direction is 41.8° below negative y-axis
Answer:

Explanation:
Given:
Initial velocity of the vehicle, 
distance between the car and the tree, 
time taken to respond to the situation, 
acceleration of the car after braking, 
Using equation of motion:
..............(1)
where:
final velocity of the car when it hits the tree
initial velocity of the car when the tree falls
acceleration after the brakes are applied
distance between the tree and the car after the brakes are applied.

Now for this situation the eq. (1) becomes:
(negative sign is for the deceleration after the brake is applied to the car.)