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2 years ago

D=? V=100mL M=1.5kg=___g

1 answer:

8 0

If you go to a website known as 'Wolfram' and type in the question they should be able to answer it. It's basically a very smart calculator. I'd add a link but I don't want to seem like I'm advertising, and it's against Brainly rules.

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Two blocks, 1 and 2, are connected by a rope R1 of negligible mass. A second rope R2, also of negligible mass, is tied to block

alekssr [168]

Answer:

Explanation:

Given

Two block are connected by rope $R_1$

$R_2$ rope is attached to block 2

suppose $F_2$ is a force applied to Rope $R_2$

Applied force $F_2$ =Tension in Rope 2

$F_2=(m_1+m_2)a---1$

where a=acceleration of system

Tension in rope $R_1$ is denoted by $F_1$

$F_1=m_1a---2$

divide 1 and 2 we get

$\frac{F_2}{F_1}=\frac{(m_1+m_2)a}{m_1a}$

also $m_1=2.11\cdot m_2$

$\frac{F_2}{F_1}=\frac{2.11m_2+m_2}{2.11m_2}$

$\frac{F_2}{F_1}=\frac{3.11}{2.11}$

$\frac{F_1}{F_2}=\frac{2.11}{3.11}$

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2 years ago

For a sine wave depicting simple harmonic motion, the smaller the amplitude of the wave, the smaller the of the pendulum from th

stiks02 [169]

Displacement , shorter

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2 years ago

Read 2 more answers

A 128.0-N carton is pulled up a frictionless baggage ramp inclined at 30.0∘above the horizontal by a rope exerting a 72.0-N pull

Elden [556K]

Answer:

(A) 374.4 J

(B) -332.8 J

(C) 0 J

(D) 41.6 J

(E) 351.8 J

Explanation:

weight of carton (w) = 128 N

angle of inclination (θ) = 30 degrees

force (f) = 72 N

distance (s) = 5.2 m

(A) calculate the work done by the rope

work done = force x distance x cos θ

since the rope is parallel to the ramp the angle between the rope and

the ramp θ will be 0

work done = 72 x 5.2 x cos 0

work done by the rope = 374.4 J

(B) calculate the work done by gravity

the work done by gravity = weight of carton x distance x cos θ

The weight of the carton = force exerted by the mass of the carton = m x g

the angle between the force exerted by the weight of the carton and the ramp is 120 degrees.

work done by gravity = 128 x 5.2 x cos 120

work done by gravity = -332.8 J

(C) find the work done by the normal force acting on the ramp

work done by the normal force = force x distance x cos θ

the angle between the normal force and the ramp is 90 degrees

work done by the normal force = Fn x distance x cos θ

work done by the normal force = Fn x 5.2 x cos 90

work done by the normal force = Fn x 5.2 x 0

work done by the normal force = 0 J

(D) what is the net work done ?

The net work done is the addition of the work done by the rope, gravitational force and the normal force

net work done = 374.4 - 332.8 + 0 = 41.6 J

(E) what is the work done by the rope when it is inclined at 50 degrees to the horizontal

work done by the rope= force x distance x cos θ
the angle of inclination will be 50 - 30 = 20 degrees, this is because the ramp is inclined at 30 degrees to the horizontal and the rope is inclined at 50 degrees to the horizontal and it is the angle of inclination of the rope with respect to the ramp we require to get the work done by the rope in pulling the carton on the ramp

work done = 72 x 5.2 x cos 20

work done = 351.8 J