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77julia77 [94]
2 years ago
5

The pupil of an eagle’s eye has a diameter of 6.0 mm. Two field mice are separated by 0.010 m. From a distance of 204 m, the eag

le sees them as one unresolved object and dives toward them at a speed of 17 m/s. Assume that the eagle’s eye detects light that has a wavelength of 550 nm in vacuum. How much time passes until the eagle sees the mice as separate objects?
Physics
1 answer:
kherson [118]2 years ago
8 0

Answer:6.74 s

Explanation:

Given

diameter\left ( D\right )=6 mm

d=0.01m

L=204 m

v=17 m/s

\lambda =550 nm

from rayleigh's critterion for resolution

\theta =\frac{1.22\lambda }{D}=\frac{d}{L'}

L'=\frac{D\cdot d}{1.22\lambda }

L'=89.418 m

t=\frac{L-L'}{v}

t=\frac{114.581}{17}=6.74 s

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A boy uses a slingshot to launch a pebble straight up into the air. The pebble reaches a height of 37.0 m above the launch point
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OverLord2011 [107]

Answer:

The magnitude of the total linear acceleration is 0.27 m/s²

b. 0.27 m/s²

Explanation:

The total linear acceleration is the vector sum of the tangential acceleration and radial acceleration.

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a_t = ar

where;

a is the angular acceleration and

r is the radius of the circular path

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\theta = \frac{1}{2} at^2\\\\0.4 = \frac{1}{2} (1.6)t^2\\\\t^2 = 0.5\\\\t = \sqrt{0.5} \\\\t = 0.707 \ s\\\\

Determine angular velocity

ω = at

ω = 1.6 x 0.707

ω = 1.131 rad/s

Now, determine the radial acceleration

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The magnitude of total linear acceleration is given by;

a = \sqrt{a_t^2 + a_r^2} \\\\a = \sqrt{0.208^2 + 0.166^2} \\\\a = 0.266 \ m/s^2\\\\a = 0.27  \ m/s^2

Therefore, the magnitude of the total linear acceleration is 0.27 m/s²

b. 0.27 m/s²

5 0
2 years ago
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