Question

A factory robot drops a 10 kg computer onto a conveyor belt running at 3.1 m/s. The materials are such that

Answer 1

Answer:

Option (c) will be correct answer that is it will go 1.6 m

Explanation:

We have given that conveyor has the velocity u = 3.1 m/sec

Mass of the robot = 10 kg

static friction coefficient  = 0.5 and kinetic friction coefficient = 0.3

Acceleration due to gravity g = 9.8 $m/sec^2$

Acceleration a = kinetic friction coefficient ×g = 0.3×9.8 = 2.94$m/sec^2$

Now according to third equation of motion

$v^2=u^2+2as$

Finally velocity of the conveyor will be zero

So $0^2=3.1^2-2\times 2.94\times s$

s = 1.6 m

So option (c) is correct option