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jekas [21]
2 years ago
3

Shaunta is developing a recursive formula to represent an arithmetic sequence in which 5 is added to each term to determine each

successive term. Which formula could represent her sequence?
Mathematics
2 answers:
motikmotik2 years ago
6 0

Answer:

a_{n+1} = a_n + 5                

Step-by-step explanation:

We are given the following in the question:

An arithmetic sequence where 5 is added to every term.

Thus, common difference, d = 5

Let the first term be

a = a_0

Then, n^{th} term of an arithmetic sequence is given by:

a_n = a_0 + (n-1)d

Putting values, we get,

a_n = a_0 + (n-1)5\\a_n = a_0 + 5n - 5\\a_{n+1} = a_0 + (n+1-1)5\\a_{n+1} = a_0 + (n-1)5 + 5\\a_{n+1} = a_n + 5

is the required recursive relation for arithmetic progression.

Hitman42 [59]2 years ago
5 0

Answer:

a f(n + 1) = f(n) + 5

Step-by-step explanation:

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One grocery store sells 8 pounds of bananas for $3.12. Another grocery store sells 9 pounds of bananas for $3.06.
lesantik [10]

Answer:

the 3rd one

Step-by-step explanation:

$3.12÷8=$0.39

$3.06÷9=$0.34

$0.39 is 0.05 more than $0.34

4 0
2 years ago
Read 2 more answers
What percent of 84 is 12?
lozanna [386]
So here is what we have

12 is what we need

out of the 84 we have

so...

12/84= .1428571429

and lets check our work

.1428571429 X 84 = 12

now lets convert it to a percent

.1428571429 X 100 = 14.28571429%

so the answer is 

14.28571429%
6 0
2 years ago
Read 2 more answers
A factory received a shipment of 38 sprockets, and the vendor who sold the items knows there are 5 sprockets in the shipment tha
weeeeeb [17]

Answer:

a) 0.00019923%

b) 47.28%

Step-by-step explanation:

a) To find the probability of all sockets in the sample being defective, we can do the following:

The first socket will be in a group where 5 of the 38 sockets are defective, so the probability is 5/38

The second socket will be in a group where 4 of the 37 sockets are defective, as the first one picked is already defective, so the probability is 4/37

Expanding this, we have that the probability of having all 5 sockets defective is: (5/38)*(4/37)*(3/36)*(2/35)*(1/34) = 0.0000019923 = 0.00019923%

b) Following the same logic of (a), the first socket have a chance of 33/38 of not being defective, as we will pick it from a group where 33 of the 38 sockets are not defective. The second socket will have a chance of 32/37, and so on.

The probability will be (33/38)*(32/37)*(31/36)*(30/35)*(29/34) = 0.4728 = 47.28%

5 0
2 years ago
Explain how complex fractions can be used to solve problems involving ratios
Kisachek [45]
When you have ratios and some unknowns you can create complex fractions from them.Bring them to the same denominator and solve for X.
8 0
2 years ago
Ayne evaluated an expression that has a value of StartFraction 1 Over 729 EndFraction. Which expression could Jayne have evaluat
Alex17521 [72]

Answer:

9 Superscript negative 3

Step-by-step explanation:

{9^{-3} = \frac{1}{9^{3}} =\frac{1}{729}}\\

3 0
2 years ago
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