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vichka [17]
2 years ago
7

Currently, in Littlefield, jobs arrive at 12 per day and you have (just) enough capacity at each station (i.e., the departure ra

te is also 12 per day). If you want to change to a contract that promises a throughput time of at most 0.25 days to reap the full profits, then what should you set your WIP Limit as
Mathematics
1 answer:
OlgaM077 [116]2 years ago
6 0

Answer:

The WIP limit is 0.50 days.

Step-by-step explanation:

The Computation of WIP limits:

to begin with, it is required to compute the process and procedure efficiency which will be computed as follows:

Value Added Time = 12 days (arriving time)

Non-Value-Added Time = 12 days (departure time)

Efficiency = Value Added / (Value Added + Non-Value Added)

                = 12 / (12+12)

                = 12 / 24

               = 0.50 or 50%

the most obligatory throughput time will be 0.25 days to realize the profits

WIP limit = Throughput time / Efficiency  

               = 0.25 / 50%

               = 0.50 days.

The WIP limit is 0.50 days.

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D2-9k+3 for d=10 and k=9
AVprozaik [17]

Answer:

22

Step-by-step explanation:

10^2-9(9)+3

100-81+3

19+3

22

8 0
2 years ago
A bakery sells rolls in units of a dozen. The demand X (in 1000 units) for rolls has a gamma distribution with parameters α = 3,
bearhunter [10]

Answer:

The value  is  E(X) =  \$ 1.7067

Step-by-step explanation:

From the question we are told that

   The  parameters  are  α = 3, θ = 0.5

    The cost of making a unit on the first day  is  c = $2

    The selling price of a  unit on the first day is  s = $5

    The selling price of a leftover unit on the second day is  v  = $ 1

Generally the profit of a unit on the first day is

        p_1 = 5 - 2

           p_1 = \$3

The profit of a unit on the second day is

       p_2 = 1 - 2

=>     p_2 = - \$1

Generally the probability of making profit greater than $ 1 is mathematically represented as

    P(X >  1 ) = Gamma (X ,\alpha , \theta)

=>   P(X >  1 ) = Gamma (1 ,3 , 0.5)

Now from the gamma distribution table  we have that

    P(X >  1 ) =  0.67668

Generally the probability of making profit less than or  equal to  $ 1 is mathematically represented as

       P(X \le  1 ) = 1 - P(X >  1 )

=>     P(X \le  1 ) = 1 - 0.67668

=>     P(X \le  1 ) = 0.32332    

So  the probability of making  $3  is    P(X >  1 ) =  0.67668

and  the probability of making  -$1  is   P(X \le  1 ) = 0.32332  

Generally the value of profit per day is mathematically represented as

      E(X) =  3 *  P(X >  1 )   +   (-1  *  P(X \le 1 ) )

=>     E(X) =  3 * 0.67668   +   (-1  *  0.32332 )

=>     E(X) =  \$ 1.7067

4 0
2 years ago
The expression y2 – 10y + 24 has a factor of y – 4. What is another factor of y2 – 10y + 24?
charle [14.2K]
We may answer the question above by dividing the expression y² - 10x + 24 with the given factor, y - 4. The division would give an answer of y - 6. Thus,

                                <span>y² - 10x + 24 = (y - 4)(y - 6)

The answer is the fourth choice, y - 6.</span>
4 0
2 years ago
If each lap in a pool is 100 meters long, how many laps equal one mile? Round to the nearest tenth. (Hint: 1 foot ≈0.3048 meter)
aalyn [17]
If each lap in a pool is 100 meters long,how many laps equal one mile Round to the nearest tenth.(Hint:1 foot=0.3048 meter) 1 mile = 5280 ft lets do a ratio: 1ft/.3034m = x ft/100m the ft and meters sybols cancel, so 1/.3048 =x/100 so 100/.3038 = x = 329.164 so there are 329.164 ft for every 100 meters to find the number of laps to get to a mile which is 5280, do another ratio 329.164ft/100 m =5280 ft/xm the left side reduces to 3.29164 =5280/x you can compute this and see that 5280/3.29164 = 1604.064 meters 1604.064 meters *1 lap / 100m = 16.04064 laps are required to make a mile
7 0
2 years ago
The lithosphere (made of Earth's crust and the very top part of the mantle) is a stiff outer layer of the Earth. Convection in t
Ilya [14]
Convection in the <u>Mantle</u> helps move pieces of the lithosphere around.
6 0
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