Answer:
12.5
Step-by-step explanation:
Let individual time taken by Anthony, Brian and Chris = t1 , t2 , t3 respectively
So, total time taken by A & B = 1 / t1 + 1 / t2 , lets suppose = 10 {i}
Total time taken by A & C = 1 / t1 + 1 / t3 , lets suppose = 15 {ii}
Total time taken by B & C = 1 / t2 + 1 / t3 , lets suppose = 20 {iii}
From {i} , 1 / t2 = 10 - 1 / t1
From {ii} 1 / t1 = 15 - 1 / t3
By above two eqtns , 1 / t2 = 10 - (15 - 1 / t3)
1 / t2 = 1 / t3 - 5
Putting in {iii} , 1 / t3 - 5 + 1 / t3 = 20
2 / t3 = 25
t3 = 12.5
Answer: It's slope is zero
Step-by-step explanation:
Answer:
98% confidence interval is (-0.105 , 0.265)
Step-by-step explanation:
n1 = 75 n2 = 75
X1 = 48 X2 = 42
P1 = X1/N1 = 0.64 P2 = X2/N2 = 0.56
98% confidence interval for difference between two proportions is :
P1 - P2 <u>+</u> Z 
= 0.08 <u>+</u> 0.185
= (-0.105 , 0.265)
98% confidence interval is (-0.105 , 0.265)
Answer:
See below
Step-by-step explanation:
Remember, we have two quantifiers, the existential quantifier ∃, and the universal quantifier ∀. The existential ∃ translates to English as "for some" or "there exists", whereas ∀ means "for all" or "every". We will also use the negation operator ¬.
First, let's write the proposition using quantifiers. "There is someone in this class who does not have a good attitude" translates to "(∃x)(¬S(x))". ∃x means that there exists a person in this class x. ¬S(x) means that x, the person that exists because of the quantifier, does not have a good attitude.
The negation is "¬(∃x)(¬S(x))" or equivalently "(∀x)(S(x))". To negate a proposition using quantifiers, change the quantifier (existential to universal and viceversa) and negate the predicate (in this case we negated ¬S(x)).
In English, "(∀x)(S(x))" means "Every person in this class has a good attitude".
Answer:
StartFraction uppercase V squared minus v squared Over 2 s EndFraction = a
Step-by-step explanation:
