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kumpel [21]
2 years ago
3

Jerry measured and timed the descent of a diving bell spider in a large fish tank. The spider reached a position 412 412 inches

below the surface of the water after descending at a constant rate for 112 112 seconds. Jerry recorded this as −412 −412 inches. What is the position of the spider relative to the surface after 1 second? Enter your answer in the box.
Mathematics
2 answers:
OLEGan [10]2 years ago
7 0

Step 1

<u>Convert mixed numbers to an improper fractions</u>

4\frac{1}{2} =\frac{4*2+1}{2}= \frac{9}{2}

1\frac{1}{2} =\frac{1*2+1}{2}= \frac{3}{2}

Step 2

<u>Find the unit rate of the descending</u>

unit\ rate= \frac{(9/2)}{(3/2)}=3 \frac{inches}{sec}

therefore

<u>the answer is</u>

the position of the spider relative to the surface after 1 second is -3\ inches


otez555 [7]2 years ago
5 0
I think your answer would be 300 again i think
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