Question

23. Find the coverage area for a microcellular system where path loss follows the simplied model with γ = 3, d0 = 1, and K = 0 dB and there is also log normal shadowing with σ = 4 dB. Assume a cell radius of 100 m, a transmit power of 80 mW, and a minimum received power requirement of Pmin = −100 dBm.

Answer 1

Answer:

The answer is 93.69

Explanation:

The microcellular system is:

$C=Q(a)+exp(\frac{2-2ab}{b^{2} } )Q(\frac{2-ab}{b} )$ (eq. 1)

$Q(a)=\frac{1}{2} erfc(\frac{a}{\sqrt{2} } )$

a = (Pmin - P(R))/σ

b = (10γ*log10^e)/σ

P(R) = Pt + k - 10γ*log(R/d) = 16Bm + 0 - 10*3.*log100 = -44 Bm

$a=\frac{-100-(-44)}{4} =-14\\b=\frac{10*3*log10^{e} }{4} =\frac{10*3*0.43}{4} =3.22$

Replacing in eq. 1:

$C=Q*(-14)+exp(\frac{2-2*3.22*(-14)}{3.22^{2} } )Q(\frac{2+(-14)*3.22}{3.22^{2} } )\\C=1+exp(4.54)*1\\C=93.69$