Hello!
We are asked to find the number of lines the choir has to learn in time for a concert.
We're given that the concert is in 7 weeks, but they learn new lines each day, so we have to convert it to days. We know that there is 7 days in a week, we would multiply 7 weeks by 7 days, which is 49 days.
Now, we would take the total number of lines, which is 3016, and divide that by 49 days.
3016 lines / 49 days ≈ 61.55 lines/day
Since this is a real-world situation, we should round our answer is to nearest whole number, which would be 62 lines/day.
Therefore, Ester's choir needs to learn about 62 lines per day in time for the concert.
Answer:
c. Not significant at .055
Step-by-step explanation:
When a pair of dice is rolled, we have 6²=36 possible outcomes. Only 2 of these outcomes have a total score of 11:
- When the first dice is 5 and the second is 6.
- When the first dice is 6 and the second is 5.
Then, we can calculate the probability of getting 11 as the quotient between the successs outcomes and the total outcomes.
Then, the probability of getting 11 is:
This probability is not equal or less than 0.05, so it is not significant at 0.055.
Answer:
Step-by-step explanation:
Total money = $600
Bicycle cost = $253.98
3 bicycle reflector = 3×$7.5 =$22.5
Bicycle helmet = $42.36
Total money spent will be equal to the = $(253.98+22.5+42.36)
= $318.84
Amount remaining = $(600-318.84)
= $281.16
The number of outfit he can get at $78.12 = $281.16/78.12 = 3.60
He can get 3 outfit and have $0.60
Left
It would be 48/64 this is done by finding how many times 4 fits in 64 (64/4) then multiplying 3 by that answer
Answer:
$1,050*125x=P(x). I just need more characters.
