We have been given a system of inequalities and an objective function.
The inequalities are given as:
And the objective function is given as:
In order to find the minimum value of the objective function at the given feasible region, we need to first graph the region.
The graph of the region is shown below:
From the graph, we can see that corner points of the feasible region are:
(x,y) = (15,30),(30,15) and (30,60).
Now we will evaluate the value of the objective function at each of these corner points and then we will compare which of those values is minimum.
Hence the minimum value of objective function is 975 and it occurs at x = 15 and y = 30
Answer:
Step-by-step explanation:
Given the length of the bugs as shown;
Lady bug = 3/8
Ant = 1/4
Firefly = 7/8
Honey bee = 0.8
Deer tick = 0.2
Before we arrange the length in ascending order (shortest to longest), we will have to represent them in percentage.
Lady bug = 3/8×100
= 300/8
= 37.5%
Ant = 1/4×100
Ant = 25%
Firefly = 7/8 × 100
Firefly = 87.5%
Honey bee = 0.8×100
Honey bee = 80%
Deer tick = 0.2×100
Deer tick = 20%
On rearranging in ascending order:
20%, 25%, 37.5%, 80%, 87.5%
Based on the insect
Deer tick, Ant, ladybug, honey bee, Firefly
Based on their length:
0.2, 1/4, 3/8, 0.8, 7/8
M + 20 = 9
u need to subtract 20 from both sides because u want to isolate m
m + 20 = 9
m + 20 - 20 = 9 - 20
m = - 11
Check the picture below.
make sure your calculator is in Degree mode.
<span>In this problem, we will use the combination
since the order does not matter but the flower can only be selected once. From the
given, we have a total of 11 flower and 9 flowerpots, to get the number of
possible combinations, we can write is at 11C9 or 11! / {9! (11-9)!}. The total
number of possible combinations is 55</span>
