All categories

2 years ago

Joel is mailing a large envelope to his cousin. The envelope has pictures inside, so he doesn't want to bend it.

Mathematics

1 answer:

Nuetrik [128]2 years ago

8 0

Answer: Put a cardboard piece inside the envelope then mail it

Step-by-step explanation: If you make the cardboard piece the exact size as the pictures then put it behind all of the pictures it would make it hard for the pictures to bend if it has support.

You might be interested in

What is the equation of a line in slope intercept form that contains the points (-4,3) and (2,-6)

Nataly_w [17]

Answer:

y = (-3/2)x - 3

Step-by-step explanation:

The slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept.

Given two points, we can calculate the slope by dividing the change in y (or the difference in the y-coordinates) by the change in x (or the difference in the x-coordinates). Our two points are (-4, 3) and (2, -6):

m = (3 - (-6)) / (-4 - 2) = 9 / (-6) = -3/2

So, we can update our equation:

y = (-3/2)x + b

The y-intercept is where the graph crosses the y-axis, or the y-value where x = 0. Let's plug in 3 for y and -4 for x:

3 = (-3/2) * (-4) + b

3 = 6 + b

b = -3

So, our y-intercept is -3.

Our slope-intercept form is thus:

y = (-3/2)x - 3

<em>~ an aesthetics lover</em>

7 0

2 years ago

Let D be the smaller cap cut from a solid ball of radius 8 units by a plane 4 units from the center of the sphere. Express the v

natima [27]

Answer:

Step-by-step explanation:

The equation of the sphere, centered a the origin is given by $x^2+y^2+z^2 = 64$ . Then, when z=4, we get

$x^2+y^2= 64-16 = 48$ .

This equation corresponds to a circle of radius $4\sqrt[]{3}$ in the x-y plane

c) We will use the previous analysis to define the limits in cartesian and polar coordinates. At first, we now that x varies from $-4\sqrt[]{3}$ up to $4\sqrt[]{3}$ . This is by taking y =0 and seeing the furthest points of x that lay on the circle. Then, we know that y varies from $-\sqrt[]{48-x^2}$ and $\sqrt[]{48-x^2}$ , this is again because y must lie in the interior of the circle we found. Finally, we know that z goes from 4 up to the sphere, that is , z goes from 4 up to $\sqrt[]{64-x^2-y^2}$

Then, the triple integral that gives us the volume of D in cartesian coordinates is

$\int_{-4\sqrt[]{3}}^{4\sqrt[]{3}}\int_{-\sqrt[]{48-x^2}}^{\sqrt[]{48-x^2}} \int_{4}^{\sqrt[]{64-x^2-y^2}} dz dy dx$ .

b) Recall that the cylindrical coordinates are given by $x=r\cos \theta, y = r\sin \theta,z = z$ , where r corresponds to the distance of the projection onto the x-y plane to the origin. REcall that $x^2+y^2 = r^2$ . WE will find the new limits for each of the new coordinates. NOte that, we got a previous restriction of a circle, so, since $\theta[\tex] is the angle between the projection to the x-y plane and the x axis, in order for us to cover the whole circle, we need that [tex]\theta$ goes from 0 to $2\pi$ . Also, note that r goes from the origin up to the border of the circle, where r has a value of 4\sqrt[]{3}. Finally, note that Z goes from the plane z=4 up to the sphere itself, where the restriction is \sqrt[]{64-r^2}. So, the following is the integral that gives the wanted volume

$\int_{0}^{2\pi}\int_{0}^{4\sqrt[]{3}} \int_{4}^{\sqrt[]{64-r^2}} rdz dr d\theta$ . Recall that the r factor appears because it is the jacobian associated to the change of variable from cartesian coordinates to polar coordinates. This guarantees us that the integral has the same value. (The explanation on how to compute the jacobian is beyond the scope of this answer).

a) For the spherical coordinates, recall that $z = \rho \cos \phi, y = \rho \sin \phi \sin \theta, x = \rho \sin \phi \cos \theta$ . where $\phi$ is the angle of the vector with the z axis, which varies from 0 up to pi. Note that when z=4, that angle is constant over the boundary of the circle we found previously. On that circle. Let us calculate the angle by taking a point on the circle and using the formula of the angle between two vectors. If z=4 and x=0, then y=4 $\sqrt[]{3}$ if we take the positive square root of 48. So, let us calculate the angle between the vector $a=(0,4\sqrt[]{3},4)$ and the vector b =(0,0,1) which corresponds to the unit vector over the z axis. Let us use the following formula

$\cos \phi = \frac{a\cdot b}{||a||||b||} = \frac{(0,4\sqrt[]{3},4)\cdot (0,0,1)}{8}= \frac{1}{2}$

Therefore, over the circle, $\phi = \frac{\pi}{3}$ . Note that rho varies from the plane z=4, up to the sphere, where rho is 8. Since $z = \rho \cos \phi$ , then over the plane we have that $\rho = \frac{4}{\cos \phi}$ Then, the following is the desired integral

$\int_{0}^{2\pi}\int_{0}^{\frac{\pi}{3}}\int_{\frac{4}{\cos \phi}}^{8}\rho^2 \sin \phi d\rho d\phi d\theta$ where the new factor is the jacobian for the spherical coordinates.

d ) Let us use the integral in cylindrical coordinates

$\int_{0}^{2\pi}\int_{0}^{4\sqrt[]{3}} \int_{4}^{\sqrt[]{64-r^2}} rdz dr d\theta=\int_{0}^{2\pi}\int_{0}^{4\sqrt[]{3}} r (\sqrt[]{64-r^2}-4) dr d\theta=\int_{0}^{2\pi} d \theta \cdot \int_{0}^{4\sqrt[]{3}}r (\sqrt[]{64-r^2}-4)dr= 2\pi \cdot (-2\left.r^{2}\right|_0^{4\sqrt[]{3}})\int_{0}^{4\sqrt[]{3}}r \sqrt[]{64-r^2} dr$

Note that we can split the integral since the inner part does not depend on theta on any way. If we use the substitution $u = 64-r^2$ then $\frac{-du}{2} = r dr$ , then

$=-2\pi \cdot \left.(\frac{1}{3}(64-r^2)^{\frac{3}{2}}+2r^{2})\right|_0^{4\sqrt[]{3}}=\frac{320\pi}{3}$

3 0

2 years ago

Ana played 555 rounds of golf, and her lowest score was an 808080.

laiz [17]

Answer:

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Sarah is planning to spend a week at her friend's summer house in Miami Beach. All meals will be provided by her friend's parent

Rus_ich [418]

Answer:

500$

Step-by-step explanation:

5 0

2 years ago

Select all of the answers below that are equivalent to T = {Tinkey-Winky, Laa-Laa,

stepan [7]

Answer:

{thermometer, fridge, rusty nail, deoderant}
{credit card, face wash, tweezers, shovel}
{clothes, glass, car, greeting card}

Step-by-step explanation:

The options that will be equivalent to T will have to be the options that have the same Cardinality as T. Cardinality refers to the number of elements in a set and in the set T, there are 4 elements being Tinkey-Winky, Laa-Laa, Dipsy, Po so the Cardinality is 4.

The equivalent sets would therefore be sets with a cardinality of 4 as well and those are;

{thermometer, fridge, rusty nail, deoderant}
{credit card, face wash, tweezers, shovel}
{clothes, glass, car, greeting card}

3 0

2 years ago