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Alexus [3.1K]
2 years ago
3

Yuto and Riko went for a bike ride on the same path. When Riko left their house, Yuto was 5.25 miles along the path. If Yuto’s a

verage speed was 0.25 miles per minute and Riko’s average speed was 0.35 miles per minute, then Riko will be behind Yuto when 0 ≤ t < 52.5, where t is time in minutes. Explain what this solution means and why t cannot be less than zero.
Mathematics
2 answers:
poizon [28]2 years ago
5 0
To understand the meaning of that expression, I prefer to derive it myself.

Call R the position of Riko and Y the position of Yuto.

R = 0.35*t

Y = 5.25 + 0.25*t

Riko is behind Yuto while R < Y

=> 0.35t < 5.25 + 0.25t

=> 0.35t - 0.25t < 5.25

=> 0.10t < 5.25

=> t < 5.25 / 0.10

=> t < 52.5

Given that the time starts to count since both Riko left and Yuto was 5.25 miles away, the time is always zero or positive.

Then, 0 ≤ t < 52.5 is the range of time for which Riko has not reached Yuto, and is behind him.
 
bagirrra123 [75]2 years ago
3 0

Answer:

Riko will be behind Yuto from the time she leaves her house until 52.5 minutes into her ride.

t = 0 represents the time that Riko leaves her house.

Time cannot be negative.

Step-by-step explanation: just did it

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