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tatiyna
2 years ago
10

A population that consists of 500 observations has a mean of 40 and a standard deviation of 15. A sample of size 100 is taken at

random from this population. The standard error of the sample mean equals:
a. 2.50.
b. 12.50.
c. 1.343.
d. 1.50.
Mathematics
1 answer:
Alex17521 [72]2 years ago
7 0

Answer:

<h3>The option D) 1.50 is correct</h3><h3>That is the standard error of the sample mean is 1.50</h3>

Step-by-step explanation:

Given that a population that consists of 500 observations has a mean of 40 and a standard deviation of 15.

A sample size is 100  taken at random from the given population.

<h3>To find the standard error of the sample mean :</h3>

From the given Mean=40 and \sigma =15

For N=100

<h3>The formula for standard error is SE_{mean}=\frac{\sigma}{\sqrt{N}}</h3>

Substitute the values in the above formula we get

SE_{mean}=\frac{15}{\sqrt{100}}

=\frac{15}{10}

=1.50

∴ SE_{mean}=1.50

<h3>∴ The standard error of the sample mean is 1.50</h3><h3>Hence the option D) 1.50 is correct</h3>
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Answer:

  • $500

Step-by-step explanation:

<h3>Given</h3>
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<h3>To find</h3>
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<h3>Solution</h3>

<u>Equations as per given are:</u>

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<u>Subtract equation 1 from equation 3:</u>

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<u>Considering this in the equation 2:</u>

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<u>Substituting s in the equation 1:</u>

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<u>Answer:</u> Love seat costs $500

6 0
2 years ago
A factory produces 1,250,000 toys each year. The number of toys is expected to increase by about 150% per year. Which model can
kozerog [31]

Answer: Our required model is n=1250000(1.15)^t

Step-by-step explanation:

Since we have given that

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Every year is expected to increase by about 150% pr year.

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Let the number of time = t years.

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n=P(1+\dfrac{r}{100})^t\\\\n=1250000(1+\dfrac{150}{100})^t\\\\n=1250000(1+1.50)^t\\\\n=1250000(1.15)^t

Hence, our required model is n=1250000(1.15)^t

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2 years ago
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Answer:

We reject H₀.  We support that the new average credit card debt is bigger than the previous average

Step-by-step explanation:

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μ   = 8189

σ  =  690

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x  =  8776

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a) Hypothesis Test:

Null Hypothesis                        H₀            x  =  μ   = 8189

Alternative Hypothesis           Hₐ             x >  μ

b) z(c)  Alternative Hypothesis establishes that the test is a one tail-test to the right.

z(c)   for significance level  α = 0.05    is  from z-table      z(c) = 1,64

c) z(s)  =  (  x  -   μ ) / σ /√n

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d) Comparing   z(c)    and z(s)

z(s)  >  z(c)   Then z(c) is in the rejection region and we reject H₀

e) We have evidence that at 95 % of confidence the new value for the debt in credit card is now bigger than the average

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