Answer:
m∠FJH=60°
Step-by-step explanation:
The complete question is
JG bisects FJH, FJG= (2x + 4)° and GJH = (3x -9)°
What is FJH
we know that
m∠FJH=m∠FJG+m∠GJH -----> equation A
If ray JG is an angle bisector of ∠FJH
then
m∠FJG=m∠GJH -----> equation B
substitute the given values in equation B and solve for x
(2x + 4)°=(3x -9)°
3x-2x=4+9
x=13
Find the measure of angle FJH
m∠FJH=(2x + 4)°+(3x -9)°
substitute the value of x
m∠FJH=(2(13) + 4)°+(3(13) -9)°
m∠FJH=(30)°+(30)°
m∠FJH=60°
1.) RS ⊥ ST, RS ⊥ SQ, ∠STR ≅ ∠SQR | Given
2.) RS≅RS | Reflexive Property
3.) △RST ≅ △RSQ | AAS Triangle Congruence Property
146 minutes in total. One student =3 minutes. So then 42x3= 126. Class picture is 10x2=20. So then add both of them you get 146.
Answer:
For a = 1.22 there is one solution where y = 1.3
Step-by-step explanation:
Hi there!
Let´s write the system of equations:
a(0.3 - y) + 1.1 +2.4x(y-1.2) = 0
-1.2(x-0.5) = 0
Let´s solve the second equation for x:
-1.2(x-0.5) = 0
x- 0.5 = 0
x = 0.5
Now let´s repalce x = 0.5 and y = 1.3 in the first equation and solve it for a:
a(0.3 - y) + 1.1 +2.4x(y-1.2) = 0
a(0.3 - 1.3) + 1.1 + 2.4(0.5)(1.3 -1.2) = 0
a(-1) + 1.1 + 1.2(0.1) = 0
-a + 1.22 = 0
-a = -1.22
a = 1.22
Let´s check the solution and solve the system of equations with a = 1.22. Let´s solve the first equation for y:
1.22(0.3 - y) + 1.1 +2.4(0.5)(y-1.2) = 0
0.366 - 1.22y + 1.1 + 1.2 y - 1.44 = 0
-0.02y +0.026 = 0
-0.02y = -0.026
y = -0.026 / -0.02
y = 1.3
Then, the answer is correct.
Have a nice day!