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WITCHER [35]
2 years ago
7

Write a function sample_median(n,P) that generates n random values using distribution P and returns the median of the collected

sample. Hint: Use function random.choice() to sample data from P and median() to find the median of the samples * Sample run * print(sample_median(10,[0.1 0.2 0.1 0.3 0.1 0.2])) print(sample_median(10,[0.1 0.2 0.1 0.3 0.1 0.2])) print(sample_median(5,P=[0.3,0.7]) print(sample_median(5,P=[0.3,0.7]) * Expected Output * 4.5 4.0 2.0 1.0
Computers and Technology
1 answer:
TiliK225 [7]2 years ago
7 0

Answer:

import numpy as np

def sample_median(n, P):  

   return np.median( np.random.choice ( np.arange (1, len(P) + 1 ), n, p = P ) )

print(sample_median(10,[0.1 0.2 0.1 0.3 0.1 0.2]))

print(sample_median(10,[0.1 0.2 0.1 0.3 0.1 0.2]))

print(sample_median(5, [0.3,0.7])

print(sample_median(5, [0.3,0.7])

Explanation:

  • Bring in the numpy library to use the median function provided by the numpy library.
  • Define the sample_median function that takes in 2 parameters and returns the median with the help of built-in random, choice and arrange functions.
  • Call the sample_median function by providing some values to test and then display the results.    

Output:

4.5

4.0

2.0

1.0

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#You may modify the lines of code above, but don't move them! #When you Submit your code, we'll change these lines to #assign di
Musya8 [376]

Answer:

The solution code is written in Python:

  1. mystery_string = "Programming"
  2. output = ""
  3. for x in mystery_string:
  4.    output += x  
  5.    print(output)

Explanation:

Firstly, create a variable mystery_string to hold a random string (Line 1).

Create an output variable to hold an output string (Line 2).

Create a for-loop to traverse the mystery_string character by character (Line 4). In the iteration, get a character from the mystery_string, and concatenate it with output string (Line 5). Print the output string (Line 6) before proceed to the next iteration.

8 0
2 years ago
Your computer has a quad-core processor that supports multithreading installed. given that the system is running windows, how ca
AlexFokin [52]
By using cpu-z or the performance ran in taskmgr
8 0
2 years ago
What is retrieved from a search containing two terms separated<br> by the AND operator?
egoroff_w [7]

Answer:

A AND B= 1 or 0

1 1  1

0 1  0

1 0  0

0 0 0

So, as explained above if both are 1 we then only get 1, or else we get 0 always in case of AND which is a logical operator, whose output can be 0 or 1 only. This is being depicted above.

Explanation:

If both are 1 we get 1 or always else, we get the output =0.

8 0
2 years ago
B. Write a function that takes one double parameter, and returns a char. The parameter represents a grade, and the char represen
9966 [12]

Answer:

#include <iostream>

#include <cstdlib>

using namespace std;

char grade(double marks){

   if(marks>=90)

   {

       return 'A';

   }

   else if (marks >=80 && marks<90)

   {

       return 'B';

   }

   

   else if (marks >=70 && marks<80)

   {

       return 'C';

   }

   

   else if (marks >=60 && marks<70)

   {

       return 'D';

   }

     else if ( marks<60)

   {

       return 'F';

   }

}

int main()

{

   double marks;

cout <<"Ener marks";

cin >>marks;

char grd=grade(marks);

cout<<"Grae is "<<grd;

return 0;

}

Explanation:

Take input from user for grades in double type variable. Write function grade that takes a parameter of type double as input. Inside grade function write if statements defining ranges for the grades. Which if statement s true for given marks it returns grade value.

In main declare a variable grd and store function returned value in it.

3 0
2 years ago
7.8.1: Function pass by reference: Transforming coordinates. Define a function CoordTransform() that transforms the function's f
Lilit [14]

Answer:

Here is the CoordTransform() function:              

void CoordTransform(int xVal, int yVal, int &xValNew, int &yValNew){

xValNew = (xVal + 1) * 2;

yValNew = (yVal + 1) * 2; }

The above method has four parameters xVal  and yVal that are used as input parameters and xValNew yValNew as output parameters. This function returns void and transforms its first two input parameters xVal and yVal into two output parameters xValNew and yValNew according to the formula: new = (old + 1) *

Here new variables are xValNew  and yValNew and old is represented by xVal and yVal.

Here the variables xValNew and yValNew are passed by reference which means any change made to these variables will be reflected in main(). Whereas variables xVal and yVal are passed by value.

Explanation:

Here is the complete program:

#include <iostream>

using namespace std;

void CoordTransform(int xVal, int yVal, int &xValNew, int &yValNew){

xValNew = (xVal + 1) * 2;

yValNew = (yVal + 1) * 2;}

int main()

{ int xValNew;

int yValNew;

int xValUser;

int yValUser;

cin >> xValUser;

cin >> yValUser;

CoordTransform(xValUser, yValUser, xValNew, yValNew);

cout << "(" << xValUser << ", " << yValUser << ") becomes (" << xValNew << ", " << yValNew << ")" << endl;

return 0; }

The output is given in the attached screenshot   

7 0
2 years ago
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