The whole Activity , poem and paragraph is missing in the question.
Answer:
(1) Liquid A
(2) Solid A
Explanation:
Using this part of the given poem
Substances and mixtures behave differently,
During boiling and melting most especially
Boiling point of substance is fixed while mixture is not
Substance melts completely but mixture does not
The boiling point of the Pure substance remain fixed after reaching its boiling point this is shown by Liquid A
Solid A is melting completely so Solid A is a pure substance.
Answer:
D.
The concentration of reactants and the concentration of products are constant.
Explanation:
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First step is to balance the reaction equation. Hence we get
P4 + 5 O2 => 2 P2O5
Second, we calculate the amounts we start with
P4: 112 g = 112 g/ 124 g/mol – 0.903 mol
O2: 112 g = 112 g / 32 g/mol = 3.5 mol
Lastly, we calculate the amount of P2O5 produced.
2.5 mol of O2 will react with 0.7 mol of P2O5 to produce 1.4
mol of P2O5.
This is 1.4 * (31*2 + 16*5) = 198.8 g
Q = m x c x ΔT
2500 = 0.135 x C x 80.5
2500 = 10.8765 x C
C = 230.043 J/Kg.K
hope this helps
According to Raoult's law:
-(1)
where
is observed vapor pressure of the solution,
is mole fraction of solvent, and
is vapor pressure of the pure solvent.
Vapor pressure of benzene =
(given)
Reduction in vapor pressure on addition of non-volatile solute = 10.0 % (given)
So, vapor pressure of the component in the solution = 
Substituting the values in formula (1):


Mole of benzene = 
Mole of benzene = 
Since, 
So, 


Hence, moles of a nonvolatile solute to be added is
.