Given f(x)=3x²-5x-2
a) To find f(a+h) replace x with a+h in the given function. So,
f(a+h)=3(a+h)²-5(a+h)-2
=3(a²+2ah+h²)-5(a+h)-2 By using the formula (x+y)²=x²+2xy+y².
=3a²+6ah+3h²-5a-5h-2 By distributing property.
b) Similarly to find f(a) we need to replace x with a. So,
f(a)=3a²-5a-2
So, f(a+h)-f(h)= (3a²+6ah+3h²-5a-5h-2)-(3a²-5a-2)
=3a²+6ah+3h²-5a-5h-2-3a²+5a+2.
=6ah+3h^2-5h (All other terms has been cancel out)
Given:
On the first day, she drove 650 miles in 10 hours.
On the second day, she got a later start and drove 540 miles in 8 hours.
To find:
Difference between average speed of second day and first day.
Solution:
We know that,
On the first day, she drove 650 miles in 10 hours. So, the average speed is
So, the average speed on first day is 65 miles per hour.
On the second day, she got a later start and drove 540 miles in 8 hours.
So, the average speed on second day is 67.5 miles per hour.
Difference between average speed is
Therefore, the average speed on the second day is 2.5 miles per hour is faster than first day.
Answer:
A) Slope - 1.1889. The Predicted distance the drivers were able to drive increases by 1.1889
Step-by-step explanation:
Answer:
Step-by-step explanation:
The verbiage "five and nine tenths" can refer to the mixed number 5 9/10, or to the decimal in standard form, 5.9. Simply converting the phrase to a decimal gets you the standard form.
The expanded form can be written a number of ways, depending on how you like to show the place value multipliers. The simplest expanded form is simply the sum of the digits:
5 + 0.9
You can show the multipliers in standard form:
5×1 + 9×0.1
Or, you can show the multipliers in exponential form:
5×10⁰ +9×10⁻¹
