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2 years ago

9

Consider the electrolysis of aqueous agno3. Refer to the table of standard reduction potentials as needed. What should form at t

he cathode?

1 answer:

Valentin [98]2 years ago

8 0

Answer:

Ag+

Explanation:

anode: 2AgNO3(l)⟶Ag(aq)+NO3(g)

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Consider the following reactions and their respective equilibrium constants: NO(g)+12Br2(g)⇌NOBr(g)Kp=5.3 2NO(g)⇌N2(g)+O2(g)Kp=2

maxonik [38]

Answer:

Equilibrium constant of the given reaction is $1.3\times 10^{-29}$

Explanation:

$NO+\frac{1}{2}Br_{2}\rightleftharpoons NOBr$ .... $(K_{p})_{1}=5.3$

$2NO\rightleftharpoons N_{2}+O_{2}$ .... $(K_{p})_{2}=2.1\times 10^{30}$

The given reaction can be written as summation of the following reaction-

$2NO+Br_{2}\rightleftharpoons 2NOBr$

$N_{2}+O_{2}\rightleftharpoons 2NO$

......................................................................................

$N_{2}+O_{2}+Br_{2}\rightleftharpoons 2NOBr$

Equilibrium constant of this reaction is given as-

$\frac{[NOBr]^{2}}{[N_{2}][O_{2}][Br_{2}]}$

$=(\frac{[NOBr]}{[NO][Br_{2}]^{\frac{1}{2}}})^{2}(\frac{[NO]^{2}}{[N_{2}][O_{2}]})$

$=\frac{(K_{p})_{1}^{2}}{(K_{p})_{2}}$

$=\frac{(5.3)^{2}}{2.1\times 10^{30}}=1.3\times 10^{-29}$

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2 years ago

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Enter the numbers 1 to 5 to put in order the steps for lighting a Bunsen burner.

ivanzaharov [21]

The correct steps in lighting a Bunsen burner would be as follows: First, clean the area. Get rid of any flammable substances near the burner. Second, close the air supply Third, turn on the gas supply to the burner. Fourth, use a lighter to light the flame. Fifth, adjust the flow of air to control the flame.

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Chromium has three naturally-occurring isotopes. It is 80% Chromium-52, 14% Chromium-53, and 6% Chromium-51. What is the average

katrin2010 [14]

Answer:

20

Explanation:

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2 years ago

how are pure carbon, oxygen and hydrogen different from the compound ethanol which contains all three of those elements?

DENIUS [597]

Carbon, oxygen, & hydrogen may all be elements found in ethanol, but when separated, they have completely different chemical compounds. They are pure elements where as ethanol is a mixture.

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2 years ago

A beaker has 0.2 M of Na2SO4. What will be the concentration of sodium and sulfate ions?

netineya [11]

The concentration of sodium and sulphate ions are [ $Na^+$ ] = 0.4 M, [ $SO_4^2-$ ] = 0.2 M

Explanation:

The molar concentration is defined as the number of moles of a molecule or an ion in 1 liter of a solution.

In the given solution, the concentration of the salt sodium sulphate is 0.2M. So, 0.2 moles of sodium sulphate is present in 1 liter of solution.

Assuming 100% dissociation,

1 molecule of sodium sulphate gives 2 ions of sodium and 1 ion of sulphate.

So 0.2 moles of sodium sulphate will give 0.4 moles of sodium ions and 0.2 moles of sulphate ions.

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2 years ago