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notka56 [123]
2 years ago
14

There is a number, which has five digits 5abc9. If this number is the square of an integer, where a,b,c each represent a missing

digit and all five digits are different, then find this number.
Mathematics
1 answer:
ivanzaharov [21]2 years ago
5 0

Answer:

54289

Step-by-step explanation:

233^2

I knew the last digit had to be a 3 because the last number is 9 and the number had to be less than 300 because that is 90000 so I just used trial and error to get the answer.

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A) The sum of −3x+5 and 7−4x is subtracted from 5x+17.
AlekseyPX
A. -3x+5+7-4x 
  -3x-4x+5+7 
-7x+12 

-7x+12-5x+17 
-7x-5x+12+17
-12x+29

B. -5*(x+2)= -5x-10
-6x-1+ (-5x-10)= -6x-5x-1-10=
  -11x-11

8 0
2 years ago
An Olympic athlete of mass 80kg competes in a 100m race. What is the best estimate of his mean kinetic energy during the race?
kipiarov [429]
For this question, you need to know that the average velocity of a 100m Olympic athlete is 10 m/s before you start solving the equation. The equation is K (energy in Jules) = 1/2 mv^2 (where m is the mass in kg and v the speed in meters per second). 
The correct answer is 4000J. To see how I got it, take a look at the attachment. 

3 0
2 years ago
The aquarium at Sea Critters Depot contains 140 fish. Eighty of these fish are green swordtails (44 female and 36 male) and 60 a
maxonik [38]

Given that:

Total number of fish = 140

Fish are green swordtails female = 44

Fish are green swordtails male = 36

Fish are orange swordtails female = 36

Fish are orange swordtails male = 24

Solution:

A. We have to find the probability that the selected fish is a green swordtail.

\text{P(green swordtail)}=\dfrac{\text{Total green swordtail fish}}{\text{Total fish}}

\text{P(green swordtail)}=\dfrac{80}{140}

\text{P(green swordtail)}=\dfrac{4}{7}

Therefore, the probability that the selected fish is a green swordtail is \dfrac{4}{7}.

B.  We have to find the probability that the selected fish is male.

\text{P(Male fish)}=\dfrac{\text{Total male fish}}{\text{Total fish}}

\text{P(Male fish)}=\dfrac{36+24}{140}

\text{P(Male fish)}=\dfrac{60}{140}

\text{P(Male fish)}=\dfrac{3}{7}

Therefore, the probability that the selected fish is a male, is \dfrac{3}{7}.

C. We have to find the probability that the selected fish is a male green swordtail.

\text{P(Male green swordtail)}=\dfrac{\text{Total male green swordtail fish}}{\text{Total fish}}

\text{P(Male green swordtail)}=\dfrac{36}{140}

\text{P(Male green swordtail)}=\dfrac{9}{35}

Therefore, probability that the selected fish is a male green swordtail is \dfrac{9}{35}.

D.

We have to find the probability that the selected fish is either a male or a green swordtail.

\text{P(Male or green swordtail)}=\dfrac{\text{Total male or green swordtail fish}}{\text{Total fish}}

\text{P(Male or green swordtail)}=\dfrac{44+36+24}{140}

\text{P(Male or green swordtail)}=\dfrac{96}{140}

\text{P(Male or green swordtail)}=\dfrac{24}{35}

Therefore, the probability the selected fish is either a male or a green swordtail is \dfrac{24}{35}.

4 0
2 years ago
the local volleyball team hosts a concession stand to raise money. They can spend $120 to purchase popcorn, candy, and drinks. t
Art [367]
To solve this question, I did an equation:
0.75x + 1.20y = 120
0.75(95) + 1.20(35) = 120
Then multiply:
71.25 + 42 = 120
Now to check:
71.25 + 42 = 113.25
Answer: 120 - 113.25 = $6.75 Hope this helps

7 0
2 years ago
Your school wants to take out an ad in the paper congratulating the basketball team on a successful​ season, as shown to the rig
Serga [27]

Answer:

1.4in

Step-by-step explanation:

Length of Photo = 4in

Width of Photo = 3in

Unknown:

Value of X = ?

Solution:

Follow these steps:

  Area of a rectangle  = l x w

Since the photo is a rectangle; area of photo:

  Area of photo  = 4in x 3in = 12in²

For the area of the ad;

   Length of ad  = 4 + x

   Width of ad = 3 + x

Given that,

                  the area of the photo  = \frac{1}{2} area of ad

                           12in²  = \frac{1}{2} area of ad

                   Area of ad  = 24in²

Area of the ad;

             (4 + x) (3 + x)  = 24

               12 + 4x + 3x + x² = 24

                12 + 7x + x²  = 24

                       x² + 7x = 24 - 12

                       x² + 7x = 12

                     x² + 7x - 12  = 0

            Using the almighty formula where

     a  = 1, b = 7 and c = -12

          x  = \frac{-b (+/-) \sqrt{b^{2} } - 4ac}{2a}

     

          x = \frac{-7 + \sqrt[]{-7^{2} - 4x1x-12 } }{2x1}   or \frac{-7 - \sqrt[]{-7^{2} - 4x1x-12 } }{2x1}

          x  = 1.4  or  -8.4

therefore the answer is 1.4in

x is 1.4in

4 0
1 year ago
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